Are these ratios equivalent? $4,000 for 10,000 units $3,000 for 4,000 units

Please help!

Gemiola [76]

The derivative of $f(x) = 2\cdot x^{2}-9$ is $f'(x) = 4\cdot x$ .

In this exercise we must apply the definition of derivative, which is described below:

$f'(x) = \lim_{x \to 0} a_n \frac{f(x+h)-f(x)}{h}$ (1)

If we know that $f(x) = 2\cdot x^{2}-9$ , then the derivative of the expression is:

$f'(x) = \lim_{h \to 0} \frac{2\cdot (x+h)^{2}-9-2\cdot x^{2}+9}{h}$

$f'(x) = 2\cdot \lim_{h \to 0} \frac{x^{2}+2\cdot h\cdot x + h^{2}-2\cdot x^{2}}{h}$

$f'(x) = 2\cdot \lim_{h \to 0} 2\cdot x + h$

$f'(x) = 4\cdot x$

The derivative of $f(x) = 2\cdot x^{2}-9$ is $f'(x) = 4\cdot x$ .

We kindly invite to check this question on derivatives: brainly.com/question/23847661

4 0

3 years ago

If the first step in the solution of the equation -8 - 7x = -5x - 10 is "add 10," then what should the next step be?

dolphi86 [110]

-8 - 7x = -5x - 10....add 10 to both sides
2 - 7x = -5x ......NEXT STEP.....add 7x to both sides

7 0

3 years ago

Read 2 more answers

What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)

olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.

For example:

Type of change Effect on y = f(x)

$y = f(x - c)$ horizontal shift: c units to right

So

Considering the function

$f(x) = x^2$

The graph is shown below. The first figure is representing $f(x) = x^2$ .

Now, considering the function

$\:f\left(x\right)=\left(x-6\right)^2$

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shown below in second figure. It is clear that the graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shifted 6 units to the right as compare to the function $f(x) = x^2$ .

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

5 0

3 years ago

I NEED HELP ASAP!!! WHAT IS THIS ANSWER

Softa [21]

Answer:

the first one is 3

second one is 7

third one -2

fourth one -3

Step-by-step explanation:

7 0

3 years ago

The function g(x) is a transformation of the cube root parent function,

Bad White [126]

Answer:

C

Step-by-step explanation:

Apex

7 0

3 years ago