The perimeter of △ABC with vertices A(−5, 3), B(4, −5), and C(−5, −5) is 29.04 units
<h3>Perimeter of a triangle</h3>
The perimeter of a triangle is the sum of the sides of the triangle.
Given the coordinate points A(−5, 3), B(4, −5), and C(−5, −5)
Determine the distance AB, AC and BC using the distance formula
AB = √(-5-3)²+(4+5)²
AB = √64+81
AB = √145
AB = 12.04 units
AC = √(-5-3)²+(-5+5)²
AC = √64
AC = 8 units
BC = √(-5-4)²+(-5+5)²
BC = √81
BC = 9 units
Take the sum
Perimeter of triangle ABC = 9 + 8 + 12.04
Perimeter of triangle ABC = 29.04 units
Hence the perimeter of △ABC with vertices A(−5, 3), B(4, −5), and C(−5, −5) is 29.04 units
Learn more on perimeter of triangle here: brainly.com/question/24382052
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