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DIA [1.3K]
3 years ago
8

Steven's kite rose into the air at the rate of five feet per second. How many feet did it rise in 2/3 minute (please explain how

if you can)
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

800 ft

Step-by-step explanation:

2/3 minutes = 2/3 min * 60 sec/min = 40 sec

5 ft/sec * 40 sec = 800 ft

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Louis little brother is sick with a fever his temperature is 104​
valentina_108 [34]

Answer:

40

Step-by-step explanation:

C=(5/9)(104-32)

C=(5/9)(72)

C=40

4 0
3 years ago
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If you owe your friend $3 and you have $15, which expression would help you find out how much money you would have left?
Tju [1.3M]

Answer:

12

Step-by-step explanation:

15 - 3 = 12

8 0
3 years ago
For a circle with a radius of 6 meters, what is the measurement of a central angle (in degrees) subtended by an arc with a lengt
lesantik [10]
I hope this helps you




Arc length = central angle/360.2pi.r


7/3pi=?/360.2pi.6


?=7.10


?=70
8 0
3 years ago
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A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0
3 years ago
What is the greatest number of tens in 384
elena-s [515]

Answer:

30 tens

90 is the greatest number of tens

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3 years ago
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