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3 years ago

What period of the functions f(x) = cos 2x? Please help thank you.

Mathematics

1 answer:

kvv77 [185]3 years ago

3 0

Answer:

option 3 ⇒ π

Step-by-step explanation:

The general equation of the given function is as following

f(x) = A cos (Bx)

Where A is the amplitude

and B = 2π/period

For the given function f(x) = cos 2x

B = 2

period = 2π/B = 2π/2 = π

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URGENT HELP<br> Solve for X

suter [353]

Answer:

x = 3

Step-by-step explanation:

95 + 85 + 100 + 27x -1 = 360

280 + 27x - 1 = 360

279 + 27x = 360

27x = 81

x = 3

Double check your work:

95 + 85 + 100 + 27(3) - 1 = 360

95 + 85 + 100 + 81 -1 =360

360 = 360

7 0

2 years ago

Factor x^4+xy^3+x^3+y^3 completely showing work.

babymother [125]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$x^4+xy^3+x^3+y^3\\\\=x^3*x+x*y^3+x^3+y^3\\\\=x(x^3+y^3)+x^3+y^3\\\\\boxed{=(x+1)(x^3+y^3)}\\$

Thank you

4 0

2 years ago

What is the antiderivative of 3x/((x-1)^2)

Maslowich

Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx$

$=3\cdot \int \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Apply\:u-substitution:}\:u=x-1$

$=3\cdot \int \frac{u+1}{u^2}du$

$\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}$

$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

4 0

3 years ago

Can someone help me?

Tcecarenko [31]

Answer:

The slope is 2

Step-by-step explanation:

Slope formula:

m=(y2-y1)/(x2-x1)

Given:

y2 = -10

y1 = -6

x2 = 2

x1 = 4

Work:

m=(y2-y1)/(x2-x1)

m=(-10 + 6)/(2 - 4)

m= (-4)/(-2)

m = 2

8 0

2 years ago

Harmon’s Jewelry Store receives a shipment of 500 jewelry pieces, but 15 pieces are damaged. At this rate, if Mrs. Harmon places

serious [3.7K]

Answer:

She should expect 165 jewelry pieces to be damaged.

Step-by-step explanation:

5,500/500 = 11

11 x 15 = 165

5 0

2 years ago