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Yuki888 [10]
3 years ago
14

A white powder, when heated, produces a colourless gas and a black solid. Is the white powder an element? I need reasons please

:)
Chemistry
1 answer:
NeTakaya3 years ago
4 0

Answer:It is not an element because elements are the purest form of a substance; hence, they are no longer broken down by heating

Explanation:

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How many electrons does a Mn Mn atom have in its 3 d 3d subshell? number of electrons: 3 d electrons 3d electrons How many of th
Vlada [557]

Answer:

[Ar] 4s² 3d⁵ or 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵

Explanation:

Manganese electronic configuration is [Ar] 3d⁵ 4s². Manganese has 5 electrons in its 3d shell and all five electrons and unpaired maintaining parallel spin since they must obey hund's rule.

Generally electrons first enter 4s² shell filling it first before entering the 3d shell due to the lower energy 4s orbital has compared to 3d orbital. Filling of the 3d orbital must be filled parallel first before pairing begins. However in the case of manganese, it only has five electrons in its 3d orbital which will only fill it with single spins.

Due to the fact that manganese has five electrons in its 3d orbital its highly magnetic and its classified as a "ferromagnetic" substance.

Note when manganese forms a bond, it loses electrons from its 4s orbital too first to form Mn(ii) or combined from both 4s and 3d to form Mn(iii), (iv) (vi) etc.

Attached is a diagram showing how manganese atoms are arranged in its shells

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3 years ago
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What value was there in predicting the properties for gaps in Mendeleev's table?
guapka [62]

helped discover elements down the line

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2 years ago
For the reaction shown, find the limiting reactant for each of the initial quantities of reactants. 2li(s) + f2(g) → 2lif(s) 1.0
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Since, we have the reaction as,

  2Li(s) + F2(g) --> 2LiF(s)

we are only concerned with the limiting reactants. We calculate for the amount of product that can be produced with the given amount of reactants.

a. 1 g Li(1 mol / 6.941 g of Li)(2 mol LiF/2 mol Li) = 0.144 mol LiF2
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Answer: 1 g of F2

b. 10.5 g Li(1 mol/6.941 g of Li)(2 mol LiF/2 mol Li) = 1.512 mol LiF2
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c. (2.85 x 10^3 g Li)(1 mol/6.941 g of Li)(2 mol LiF/2 mol Li) = 410.60 mol LiF2
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Answer: 6.79 x 10^3 g F2
    


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Whats the definition of hydrochloric acid​
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Answer:

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