Option (a) is correct.
A reducing agent is the one which loses electrons to other substance and an oxidizing agent is one which accepts electrons.
Here, In
, Cr has oxidation number 6+ in the L.H.S of the equation, but on R.H.S its oxidation number is 0 i.e. it Cr has gained electrons such that total charge is 0.
And the oxidation state of Al in the left-hand side of equation is 0 and in right-hand side, it is +6.i.e. it has donated its electrons to Cr.
Hence, Cr is the oxidizing agent and Al is the reducing agent.
Sodium is a silver-colored metal which is soft enough to cut with a knife. It is an extremely reactive metal, and is always found naturally in ionic compounds, not in its pure metallic form. Pure sodium metal reacts violently (and sometimes explosively) with water, producing sodium hydroxide, hydrogen gas, and heat:
Chlorine is a poisonous, yellow-green gas, with a very sharp odor, a
Chemical change happen cuz these 2 elements will combine to form a new compound which’s NaCl ( table salt )
Answer:
See explanation
Explanation:
We have to remember that the formula of <u>sulfur dioxide</u> is . So, the "S" atom is the central one and the "O" atoms are in the left and right of S. Additionally, "S" and "O" atom has <u>6 valence electrons each</u>. With this in mind, we can start with a structure in which the left oxygen has 2 lone pairs and a double bond, the S atom can have a double bond a single bond and a lone pair and the right oxygen with 3 lone pairs with a single bond <u>(structure A)</u>. Now, if we move the negative charge in the right (resonance) to the middle and the double bond to the left oxygen we will obtain <u>structure B</u>. Finally, we can move the negative charge in the left to the middle and we will obtain structure C. (See figure 1).
Answer:C, 0.746 mol Ag.
1 mol Ag = 6.022 x 1023 atoms of Ag -> 4.49 x 1023 atoms of Ag x 1mol Ag/6.022 x 1023 atoms -> 0.746 mol Ag
Explanation: