2/3x - 36 ≤ 22
+36 +36
----------------------
2/3x ≤ 58
2x ≤ 174
x ≤ 87
Hope this helps!
Answer:
id say 4
Step-by-step explanation:
Answer:
if im looking at it correctly it should be the third one / c
Step-by-step explanation:
Answer:
a). L=53+3 D.... equation
b). Total length of the road after the crew has worked 31 days=146 miles
Step-by-step explanation:
Step 1
Find an expression for calculating the total length of a the road as follows;
L=F+(M×D)
where;
L=total length of the road in miles
F=starting length of the road in miles
M=number of miles per day added
D=number of days the crew has worked
In our case;
L=unknown
F=53 miles
M=3 miles per day
D=unknown
L=53+(3×D)
L=53+3 D.... equation
Solve for L when D=31 days
L=53+(3×31)
L=53+93=146
Total length of the road after the crew has worked 31 days=146 miles
Answer:C' = 7-230000/x^2
Step-by-step explanation:
Min occurs when C'=0
0=7-230000/x^2
230000/x^2=7
230000=7x^2
32857.128 = x^2
181.265 = x
Out of range.
So the min must be at an endpoint.
C(1) = 7+230000 = 230007
C(100) = 700+2300 = 3000
Since C(100)<C(1), C(100) is the minimum on the interval [1, 100]
The order size that will minimize cost is 100 units.
