It is already IN standard form. If you don't want it in standard form notation it would be 74,700
I hope it helps you get it right right
Answer:
Yes
Step-by-step explanation:
Yes it is possible to solve a quadratic equation that is not factorable over the set of integers.
The solution may vary like Integers, rationals, irrationals or complex solutions.
To find two roots of the equation we can always use the formula given below to solve a quadratic equation,
For the quadratic equation,
, we have,

If the discriminant is greater than
, we get complex roots.
Answer:
B). ∠BAC and ∠CAD
C). ∠BAE and ∠EAD
D). ∠EAD and ∠DAC
Step-by-step explanation:
As we know, a linear pair consisting of angles at a single point of the line has a sum of 180° in total. In other words, two supplementary angles together comprise a linear pair. In the given figure, <u>the pair of supplementary angles ∠BAC and ∠CAD, ∠BAE and ∠EAD, and ∠EAD and ∠DAC are the linear pairs as their sum is 180</u>°. Thus, <u>options B, C, and D</u> are the correct answers.
I think you Need to subtract or multiply them all or added them all