Answer:
exponential decay because the base is less than one
Step-by-step explanation:
Answer:
Volume ≈ 33.33 cubic feet
Step-by-step explanation:
The question is:
<em>Find the volume of a right square pyramid with base square edges measuring 5 feet each and a height of the pyramid be 4 feet.</em>
<em />
So, the base is a square with side length 5 feet.
And the height of the pyramid is 4 feet.
The volume of a pyramid is given by the formula:

Where
a is the square base side length (given as 5)
h is the height of the pyramid (given as 4)
Now we substitute and find the value:

The volume is around 33.33 cubic feet
2.43 x 10^2
Hope this helps
If there is such a scalar function <em>f</em>, then



Integrate both sides of the first equation with respect to <em>x</em> :

Differentiate both sides with respect to <em>y</em> :


Integrate both sides with respect to <em>y</em> :

Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :



Integrate both sides with respect to <em>z</em> :

So we end up with

Answer:
y=a(x-p)(x-q)
y=a(x+2+√2)(x+2-√2)
passing through point (-1,1)
substitute
1=a(-1+2+√2)(-1+2-√2)
1=a(1+√2)(1-√2)
1=a(1-2)
1=a(-1)
a=1/(-1)
a=-1
y=-(x+[2+√2])(x+[2-√2])
y=-(x2+4x+2)
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