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solong [7]
2 years ago
8

Addison wants to cut 21 centimeters of lace, but her ruler is only calibrated in millimeters. How many millimeters of lace shoul

d she cut?
Mathematics
1 answer:
GuDViN [60]2 years ago
3 0
We are given that Addison wants to cut 21 centimeters of lace. The question asks us to convert 24 centimeters into millimeters. However, to do that, we need to know how many millimeters are in a centimeter. There are 10 millimeters in a centimeter. Since centimeters are larger, we will need to multiply. Therefore, 21 × 10 is 210 millimeters, and that is how many millimeters Addison wanted to cut. Hope this helped and have a phenomenal day!
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State the range of the relation
Finger [1]

The range of the given relation is D. R = {-1, 3, 5, 8}.

Step-by-step explanation:

Step 1:

The range of a relation is the second set of values while the domain constitutes the first set of values.

There are 4 given relations with two sets of values so there would be 4 domain values and 4 range values.

Step 2:

The range of (1, -1) = -1,

The range of (2, 3) = 3,

The range of (3, 5) = 5,

The range of (4, 8) = 8.

Combining these values we get the range as {-1, 3, 5, 8} which is option D.

3 0
3 years ago
I NEED HELP ASAP PLEASE SOLVE FOR X
Marina CMI [18]
ANSWER: x = 130°

EXPLANATION: You must add given angles and then subtract from 180°.
8 0
2 years ago
Can somebody please help me with these questions?
ohaa [14]
X=7.5 area= 42
You know that the total perimeter is 39 so to find x you need to add what you already have. You’ll find there are 3 sides you don’t know the length of and all you have to do is find the shorter one which is basically 9-7=2 then add everything together and subtract it from 39 then divide it by 2 to find the two sides left
3 0
3 years ago
Solve x-15=8 Help! Thank you!
Bezzdna [24]

x-15 = 8

add 15 to each side

x = 23

3 0
3 years ago
Read 2 more answers
Rename 5/6 and 14/15 using the least common denominator.
baherus [9]

Answer:

\frac{25}{30}~and~\frac{28}{30}

  • Multiply 5 by 5 to get your first parameter.

5 * 5 = 25

  • Multiply 6 by 5 to get the denominator, or your second parameter.

5 * 6 = 30

  • For the second fraction, \frac{14}{15}, you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.

14 * 2 = 28

  • Now, multiply 15 by 2

15 * 2 = 30

  • The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.

25~and~30 -- > \frac{25}{30}

28~and~30-- > \frac{28}{30}

________________________________________________________

Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>

________________________________________________________

<h3>What have we learned?</h3>

We learned how to efficiently make fractions' deominators match.

Questions related to this topic? Ask me in the comments box, please!

8 0
2 years ago
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