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MrRissso [65]
3 years ago
6

What are the similarities and differences between the Distance and Midpoint Formulas?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
4 0
The distance formula is used to find the distance between two points in the coordinate plane. The point that is at the same distance from two points A and B on a line is called the midpoint. You calculate the midpoint using the midpoint formula.
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Phillips saves $8 each month. how many months will it take him to save at least $60
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2nd Month = $16
3rd Month = $24
4th month = $32
5th Month = $40
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7th Month = $56
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After 7 months he only has $56 bucks, not enough to hit $60, but after 8 months he finally has at least $60 (in fact, he has $64)
6 0
3 years ago
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Suppose you throw a dart at a circular target of radius 10 inches. Assuming that you hit the target and that the coordinates of
sukhopar [10]

Answer:

a) The probability is 0.04

b) The probability is 0.36

c) The pprobability is 0,25

d) The probability is 0.09

Step-by-step explanation:

Lets calculate areas:

the target has a radius of 10 inces, hence the target area has a area on 10²*π = 100π square inches.

a) A circle of 2 inches of radius has an area of 2²π = 4π square inches, hence the probability of hitting that area is 4π/100π = 1/25 = 0.04

b) If the dart s within 2 inches of the rim, then it is not at distance 8 inches from the center (that is the complementary event). The probability for the dart to be at 8 inches of the center is 8²π/100π = 64/100 = 16/25 = 0.64, thus, the probability that the dart is at distance 2 or less from the rim is 1-0.64 = 0.36.

c) The first quadrant has an area exactly 4 times smaller than the area of the target (each quadrant has equal area), thus the probability for the dart to fall there is 1/4 = 0.25

d) If the dart is within 2 inches from the rim (which has probability 0.36 as we previously computed), then it will be equally likely for the dart to be in either of the 4 quadrants (the area that is within 2 inches from the rim forms a ring and it has equal area restricted on each quadrant). Therefore, the probability for the dice to be in the first qudrant and within 2 inches from the rim is 0.36*1/4 = 0.09.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

                                   

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Volgvan
The answer is  communative. hope that helped
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