Question

Maggie is standing on a platform that is 8 feet above the ground. She throws a ball in the air that hits the ground after 2 seconds. What is the equation that represents the height h feet after t seconds?
a. h=16t2−2t+8
b. h=16t2−28t+8
c. h=−16t2+2t+8
d. h=−16t2+28t+8

Answer 1

The equation that offers the best approximation to this result is: $h = -16\cdot t^{2}+28\cdot t + 8$. (Choice D)

How to find the free fall formula for a given scenario

An object experiments a free fall when it is solely accelerated by gravity on the assumption of an uniform acceleration. The formula is described below:

$h =h_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g\cdot t^{2}$ (1)

Where:

• $h_{o}$ - Initial height, in feet.
• $v_{o}$ - Initial speed, in feet per second.
• $t$ - Time, in seconds.
• $g$ - Gravitational acceleration, in feet per square second.

If we know that $t = 2\,s$, $h_{o} = 8\,ft$, $h = 0\,ft$, $g = -32.174\,\frac{ft}{s^{2}}$, then the height formula is:

$0 = 8 +2\cdot v_{o} - \frac{1}{2}\cdot (32.174)\cdot (2)^{2}$

$0 = -56.348+2\cdot v_{o}$

$v_{o} = 28.174\,\frac{ft}{s}$

The equation that offers the best approximation to this result is: $h = -16\cdot t^{2}+28\cdot t + 8$. (Choice D)

To learn more on free fall, we kindly invite to check this verified question: brainly.com/question/13796105