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luda_lava [24]
2 years ago
11

Find the unknown factor.

Mathematics
1 answer:
pshichka [43]2 years ago
3 0
The answers is -7/6x
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Help<br><br><br><br><br><br> 4/10 as a decimal
Rom4ik [11]
0.4 is 4/10 in decimal form.
6 0
2 years ago
Read 2 more answers
Please I need help ASAP<br>pls explain your answer ​
USPshnik [31]

Answer:

47.62 cm

Step-by-step explanation:

ABCD is a rhombus. Each side measures 15 cm.

m<A = 60°.

Here are some properties of a rhombus:

Opposite angles of a rhombus are congruent.

m<C = m<A = 60°

m<ADC = m<ABC

The sum of the measures of the interior angles of a quadrilateral is 360°.

The diagonals are perpendicular bisectors of each other.

m<A + m<C + m<ADC + m<ABC = 360°

60° + 60° + 2m<ADC = 360°

2m<ADC = 240°

m<ADC = 120°

Each diagonal of a rhombus bisects a pair of congruent, opposite angles.

m<ADB + m<CDB = m<ADC

m<ADB = m<CDB

m<ADB + m<ADB = 120°

m<ADB = 60°

Triangle ABD had two angles, <A and <ADB, that measure 60°. Therefore, the third angle, <ABD also measures 60°. That makes triangle ABD an equilateral triangle.

Draw segment AT.

T is the midpoint of BD. The segment AT is the perpendicular bisector of segment BD. Triangle ATD is a 30-60-90 triangle.

Using the ratio of the lengths of the sides of a 30-60-90 triangle, we can calculate the length of AT which is the radius of circle A.

TD : AT : AD

1    : √3 :   2

AD = 15 cm

TD = AD/2

AT = √3 × TD

AT = (AD√3)/2

AT = 7.5√3 = 12.99

AQ = 12.99

perimeter = QD + PB + m(arc)PTQ + BC + CD

perimeter = (15 - 12.99) + (15 - 12.99) + 60°/360° × 2π(12.99) + 15 + 15

perimeter = 47.62

Answer: perimeter = 47.62 cm

7 0
2 years ago
PLS HELP BRAINLIEST FOR CORRECT ANSWER+20 POINTS
svetoff [14.1K]

Answer:

120 blocks total

Step-by-step explanation:

All of the little cubes have side length 2"  Thus, the 11" height of the box cannot be used entirely:  we waste the top 1" because the five layers of little cubes reach only to 10" from the bottom.

Start at the bottom of the box.  The dimensions of the bottom are 12" by 8".  Along the longer side we can lay 6 blocks (which add up to 12" and are 2" wide.  We can add 3 more such rows to fill the available 8" width of the box bottom.  That's 6*4, or 24 blocks.

We can add 4 more 6 block by 4 block layers before we have the maximum 5 layers stacked in the box.

5 layers times 24 blocks per layer comes to 120 blocks total.

7 0
2 years ago
I am needing help with this question!!
Leni [432]
The answer is C. y = - 2x - 1

hope that helps!! :)
6 0
3 years ago
HELP PLEASE! WILL GIVE BRAINLESIT ​
Rudik [331]

Answer: Hypotheses ?

Step-by-step explanation:

6 0
3 years ago
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