Question

(Distance/midpoint formula) - triangle ABC has vertices on the coordinate plane at A(-6.3, 7.2) B(2.2, 4.4) and C(5.6, -3.4) find the length of BC.

Answer 1

Answer:

8.51 units

Step-by-step explanation:

Given:

$A(-6.3,7.2),B(2.2,4.4), C(5.6,-3.4)$

Length of BC can be obtained using distance formula.

For two points $A(x_{1},y_{1})$ and $B(x_{2},y_{2})$, length of AB is given as:

$AB=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Plug in 2.2 for $x_{1}$, 4.4 for $y_{1}$, 5.6 for $x_{2}$, and -3.4 for $y_{2}$. Solve for BC

$BC=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\ BC=\sqrt{(5.6-2.2)^{2}+(-3.4-4.4)^{2}}\\ BC=\sqrt{3.4^{2}+(-7.8)^{2}}=\sqrt{72.4}=8.51$

Therefore, the length of BC is 8.51 units.