If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
Answer:
Top Right
Step-by-step explanation:
231/pi(3)^2 =8.17
Round down to 8
Answer:
19
Step-by-step explanation:
Its 19
9+10 is 19
Yeah
im just putting random words so it'll let me post this
Answer:
each bannana i think
Step-by-step explanation:
The correct is going to be “Identify the Choices”.
Hope this helps! :))
