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meriva
3 years ago
8

-El papá de Susana es carpintero y en su trabajo utiliza clavos y tornillos de distintas medidas. Ahora, le advirtieron que dent

ro del muro hay una tubería a 4 centímetros del lugar en el que clavará las maderas. Por lo que Susana quiere saber qué clavos usará su papá. Pero como la medida de los clavos viene en pulgadas, ella quiere conocer la medida en centímetros, para saber qué medida de clavos no dañaría la tubería. Completa la siguiente tabla, convirtiendo la medida de los clavos de pulgadas a centímetros. ¿Cuáles clavos debe usar el Papá de Susana para no dañar la tubería?
Mathematics
1 answer:
irinina [24]3 years ago
7 0

Answer:

la tabla no esta, asi que busque la pregunta por interenet y encontre lo siguiente:

medida de los clavos         equivalencia en

<u>en pulgadas               </u>         <u>centimetros                  </u>

1 pulgada                                      2.54 cms

¹/₂  pulgada                                   2.54 x 0.5 = 1.27 cms

³/₄  pulgada                                  2.54 x 0.75 = 1.905 cms

¹/₈  pulgada                                  2.54 x 0.125 = 0.3175 cms

3¹/₂  pulgadas                              2.54 x 3.5 = 8.89 cms

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Answer:

A 90% confidence interval to estimate the mean DRP score in Henrico County Schools  is =32±2.7280

i.e. C.I.  [29.3,34.7]

Hence the results are not significant.

Step-by-step explanation:

Given:

Total no of students =44

True mean =32

Standard deviation=11

And all 4 students score also given.

To Find:

90 % confidence interval and conclusion on it.

Solution:

Here for C.I. we required mean, standard deviation and no of students.

So mean =32,S.D.=11 and n=44

Therefore , For 90 % interval Zscore is Z=1.645

C.I.=mean±Z[Standard  deviation/Sqrt(n)]

=32±1.645[11/Sqrt(44)]

=32±1.645[1.6583]

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Now Here to commit on calculated interval we should check  value of Z-score

So we need to calculate the sample mean.

Sample mean =Sum of all values /Total no of values.

=[40+ 26 +39+ 14+ 42+ 18 +25+ 43+ 46 +27 +19+ 47+ 19 +26+ 35 +34+ 15+ 44 40+ 38+ 31+ 46 +52 +25+ 35 +35+ 33 +29 +34 +41 +49+ 28+ 42+ 47 +35 +48 +22 33+ 41 +51 +27 +14+ 54 +45]/44

=34.86

Z-score=(sample mean -true mean)/[standard deviation/Sqrt(n)]

=(34.86-32)/[11/Sqrt(44)]

Z=1.72465

For ,

P(Z≥1.72465)=0.08544

For 0.05 significance level  the results are not significant at  p<0.01.

Researcher claimed mean is not correct upto 0.05 significant level

i.e calculated mean and Sample mean are different.

Hence the results are not significant.

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Read 2 more answers
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