Ask question

Ask question

All categories

3 years ago

8

-El papá de Susana es carpintero y en su trabajo utiliza clavos y tornillos de distintas medidas. Ahora, le advirtieron que dent

ro del muro hay una tubería a 4 centímetros del lugar en el que clavará las maderas. Por lo que Susana quiere saber qué clavos usará su papá. Pero como la medida de los clavos viene en pulgadas, ella quiere conocer la medida en centímetros, para saber qué medida de clavos no dañaría la tubería. Completa la siguiente tabla, convirtiendo la medida de los clavos de pulgadas a centímetros. ¿Cuáles clavos debe usar el Papá de Susana para no dañar la tubería?

1 answer:

irinina [24]3 years ago

7 0

Answer:

la tabla no esta, asi que busque la pregunta por interenet y encontre lo siguiente:

medida de los clavos equivalencia en

<u>en pulgadas </u> <u>centimetros </u>

1 pulgada 2.54 cms

¹/₂ pulgada 2.54 x 0.5 = 1.27 cms

³/₄ pulgada 2.54 x 0.75 = 1.905 cms

¹/₈ pulgada 2.54 x 0.125 = 0.3175 cms

3¹/₂ pulgadas 2.54 x 3.5 = 8.89 cms

You might be interested in

Is k=3 a reduction or enlargement (dilation)

Verizon [17]

Answer:

It is an enlargement because k=3 is larger than 1. Anything that equals less than one (ex. k=0.25) would be a reduction.

Step-by-step explanation:

8 0

3 years ago

The mean of seven positive integers is 16. When the smallest of these seven integers is removed, the sum of the remaining six in

VashaNatasha [74]

Answer: The value of the integer that was removed = 4

Step-by-step explanation:

Sum of <em>n</em> values= Mean x <em>n</em>

Given: n = 7 , Mean = 16

Let x= integer removed.

Sum of remaining 6 integers = 6

$\Rightarrow\ x+108 = 16\times7\\\\\Rihghtarrow\ x+108= 112\\\\\Rightarrow\ x=112-108\\\\\Rightarrow\ x= 4$

Hence, the value of the integer that was removed = 4

8 0

3 years ago

What is 16 times the square root of 75 to the power of eight big brain

e-lub [12.9K]

Answer:

506250000

good luck ! :)

7 0

3 years ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

4 years ago

PLEAS PLEASE PLEASE HELP!!

jekas [21]

Using the given functions, it is found that:

Lower total cost at Jump-n-Play: 40, 64.

Lower total cost at Bounce house: 28, 8, 30.

Same total cost at both locations: 32.

<h3>What are the cost functions?</h3>

For n visits to Jump-n-play, the cost is:

J(n) = 189 + 3n.

For n visits to Bounce Word, the cost is:

B(n) = 125 + 5n.

Comparing them, we have that:

$J(n) < B(n)$

$189 + 3n < 125 + 5n$

$64 < 2n$

$n > 32$

Hence:

For less than 32 visits, the cost at Bounce World is lower.

For more than 32 visits, the cost at Jump-n-play is lower.

Hence:

Lower total cost at Jump-n-Play: 40, 64.

Lower total cost at Bounce house: 28, 8, 30.

Same total cost at both locations: 32.

More can be learned about functions at brainly.com/question/25537936

4 0

2 years ago