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Degger [83]
3 years ago
8

The Internet is a hierarchical structure linking different levels of service providers whose millions of devices supply all the

interconnections. Which of the following lists the three levels outlined in the book, in order, from the companies that own the worldwide backbone of the Internet down through the companies that specialize in maintenance and support?
Computers and Technology
1 answer:
STatiana [176]3 years ago
4 0

Answer:

Explanation:

These are the three diffrent levels listed below;

1) NSP (National Service Provider)

2) RSP (Regional Service Provider)

3) ISP (Internet Service Provider)

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Does anyone know what the name of the game is, where you click on the grey dots in a 3x3 grid and try to make them all the same
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Answer:

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Explanation:

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All computers can support multiple internal hard drives. <br><br> a. True <br><br> b. False
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False.  Some can, but some do not have space for them.  Please mark Brainliest!!!
5 0
3 years ago
2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of
allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

=  n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0
3 years ago
Why are digital signals an accurate and reliable way to record and send information?
Oduvanchick [21]

Answer:

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Explanation:

6 0
2 years ago
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