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nignag [31]
3 years ago
5

What is equation for the line that is perpendicular to y-3=-4(x+2) and passes through the point (-5,7)

Mathematics
1 answer:
jekas [21]3 years ago
4 0

Answer:

y-7=1/4(x+5)

Step-by-step explanation:

y-3=-4(x+2)

y=-4x-8+3

y=-4x-5

-----------

y-y1=m(x-x1)

y-7=m(x-(-5))

y-7=m(x+5)

perpendicular means negative reciprocal of the slope,

so the slope will be 1/4

y-7=1/4(x+5)

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