Question

What is equation for the line that is perpendicular to y-3=-4(x+2) and passes through the point (-5,7)

Answer 1

Answer:

y-7=1/4(x+5)

Step-by-step explanation:

y-3=-4(x+2)

y=-4x-8+3

y=-4x-5

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y-y1=m(x-x1)

y-7=m(x-(-5))

y-7=m(x+5)

perpendicular means negative reciprocal of the slope,

so the slope will be 1/4

y-7=1/4(x+5)