Answer:
Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .
Step-by-step explanation:
We are given that let X be the number that do some or all of their banking on the Internet.
Also; Mean, 
= 310/1000 or 0.31 and Standard deviation, 
= 14.63/1000 = 0.01463 .
We know that Z = 
~ N(0,1)
Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);
P(X <=0.13) = P( <= 
) = P(Z <= -12.303) = P(Z > 12.303)
Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.
So, after seeing the table we can say that this probability is approximately less than 0.0005% .
“Jesse bought 10 more pencils than erasers” means P = 10 + E
“A pencil costs $0.15” means that $0.15*P was spent on pencils
“an eraser costs $.22” means that $0.22*E was spent on erasers
“He paid a total of $4.46” means that $0.15*P + $0.22*E = $4.46
15*(10+E) + 22*E = 446
150 + 37E = 446
37E = 296
E = 8 Jesse bought 8 erasers
Answer:
1 week= 7 days
number of days= 9
number of weeks= 1 week and 2 days
<em>hope it helps :)</em>
<em>please mark it the brainliest!</em>
Answer:
50 - 7p = 15....subtract 50 from both sides
-7p = 15 - 50
-7p = - 35...divide both sides by -7
p = -35/-7
p = 5 <=== there are 5 players
Step-by-step explanation:
Answer:
473 rounded to the nearest hundredth, would be 400.
