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3 years ago

What is the exact circumference of the circle? Circle A with diameter 60 feet. 10π feet 20π feet 40π feet 60π feet

Mathematics

2 answers:

joja [24]3 years ago

8 0

Answer:The circumference of a circle is 2•3.14(Pi)•R(radius) or 3.14(Pi)•D(diamater).

Since we have our diameter, 60, we need to multiply it by Pi.

60Pi is your answer.

I hope this helps!

Step-by-step explanation:

Gelneren [198K]3 years ago

4 0

The circumference of a circle is 2•3.14(Pi)•R(radius) or 3.14(Pi)•D(diamater).
Since we have our diameter, 60, we need to multiply it by Pi.
60Pi is your answer.

I hope this helps!

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Is 3 pounds greater than less than or = to 50 ounces

elena-s [515]

Three pounds is less than 50 ounces. 3 pounds =48 ounces

8 0

3 years ago

What is the approximate solution to the equation 2^t =38

timurjin [86]

2^t =38

take the log of each side

log ( 2^t) = log (38)

the exponent gets multiplies

t log (2) = log (38)

divide by log 2

t = log(38)/log (2)

t≈5.2479

3 0

3 years ago

There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=

yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = $\frac{12P4}{12^{4} }$

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = $\frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }$

P(X=2) = 0.401

P(X=3) = $\frac{4C3 * 12P2}{12^{4} }$

P(x=3) = 0.025

P(X=4) = $\frac{12}{12^{4} }$

P(X=4) = 0.001

Mean, $\mu = \sum xP(x)$

$\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879$

Standard deviation, $SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}$