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2 years ago

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Determine the equation, in both factored and standard forms, of a parabola with zeros at (-2, 0) and (5, 0) and passes through t

he point (-1, -4)

1 answer:

Burka [1]2 years ago

3 0

The parabola equation in the factored and standard form are f(x) = (x + 2)(x - 5), and f(x) = (x - 3/2)² - 49/4 respectivly.

<h3>What is a parabola?</h3>

It is defined as the graph of a quadratic function that has something bowl-shaped.

We have:
Parabola with zeros at (-2, 0) and (5, 0) and passes through the point (-1, -4)

In factored forms:

f(x) = (x + 2)(x - 5)

Because zeros at (-2, 0) and (5, 0)

In the standard form:

f(x) = x² - 3x - 10 or

f(x) = (x - 3/2)² - 49/4

Thus, the parabola equation in the factored and standard form are f(x) = (x + 2)(x - 5), and f(x) = (x - 3/2)² - 49/4 respectivly.

Learn more about the parabola here:

brainly.com/question/8708520

#SPJ1

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Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t

katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on $y=x$ line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

$(x,y)\rightarrow (y,x)$

Points on line EF

$(0,6) , (-5,-2)$

On reflection of this line on $y=x$ the new points we get for line JK are

$(6,0),(-2,-5)$

Points on line GH

$(-4,9),(-9,1)$

On reflection on y=x line the new points we get for line LM are

$(9,-4),(1,-9)$

Slope of line JK

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}$

Slope of line LM

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}$

For two line to be parallel, their slopes will be same.

$m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}$

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0

3 years ago

Write an equation of a line in point-slope, slope-intercept, and standard form that has

Inga [223]

Answer:

(a) $y + 4x - 14 = 0$

(b) $y = -4x + 14$

(c) $y + 4x = 14$

Step-by-step explanation:

The formula for calculating the equation of line in point - slope form is given as :

$y-y_{1} = m(x-x_{1} )$

where m is the slope

Given from the question :

m = - 4

$x_{1}$ = 2

$y_{1}$ = 6

Substituting into the formula , we have :

$y - 6 = - 4(x - 2)$

$y - 6 = -4x + 8$

$y + 4x - 6 - 8 = 0$

$y + 4x - 14 = 0$

Therefore :

(a) the equation of the line in point - slope form is $y + 4x - 14 = 0$

(b) to write it in slope - intercept form , we will make y the subject of the formula , which will give : $y = -4x + 14$

(c) the equation of line in standard form is ; $y + 4x = 14$

5 0

3 years ago

Triangle ABC is reflected across the line y=2x to map onto triangle RST. Select all statements that are true.

Anettt [7]

The reflection transformation in the question is a rigid transformation,

therefore, the image and the preimage are congruent.

The statements that are true are;

<u>AB = RS</u>

<u>∠ABC ~ ∠RST</u>

<u>ΔABC = ΔRST</u>

<u>m∠BAC = m∠SRT</u>

Reasons:

The given parameter are;

Triangle ΔABC is reflected across the line 2·X, to map onto triangle ΔRST

Required:

To select the true statements

Solution:

A reflection is a rigid transformation, therefore, the distance between corresponding points on the image and the preimage are equal.

Therefore;

AB = RS

BC = ST

AC = RT

Given that the image formed by a reflection is congruent to the preimage, we have;

ΔABC ≅ ΔRST

∠ABC ≅ ∠RST

m∠ABC = m∠RST by the definition of congruency

∠BCA ≅ ∠STR

m∠BCA = m∠STR by the definition of congruency

∠BAC ≅ ∠SRT

m∠BAC = m∠SRT by the definition of congruency

Therefore, the true statements are;

<u>AB = RS</u>; Image formed by rigid transformation

<u>∠ABC ~ ∠RST</u>; Definition of similarity

<u>ΔABC = ΔRST</u>; By definition of congruency

<u>m∠BAC = m∠SRT</u>; by the definition of congruency

Learn more here:

brainly.com/question/11787764

7 0

3 years ago

Suppose an ant walks counterclockwise on the unit circle from the point to the endpoint of the radius that forms an angle of rad

serg [7]

Answer:

$\frac{4\pi}{3}$

Step-by-step explanation:

The original questions is suppose an ant walks counterclockwise on a unit circle from the point (1,0) to the endpoint of the radius that forms an angle of 240 degrees with the positive horizontal axis.

To find the distance ant walked we find the arc length of the sector with central angle 240 degree and radius =1 (unit circle)

arc length of a sector = $\frac{centralangle}{360} \cdot 2\pi r$

arc length of a sector = $\frac{240}{360} \cdot 2\pi(1)$

arc length of a sector = $\frac{2}{3} \cdot 2\pi$

$\frac{4\pi}{3}$

6 0

3 years ago

HELP PLEASE I HAVE ONLY A FEW MINUTES TO GET THIS DONE.

oee [108]

Answer:

x=5.5

Step-by-step explanation:

LN and KM intersect and are in the same rectangle, which makes them the same line essentially. Set 49 equal to 6x+16 and then solve to get x by itself.

5 0

3 years ago

Read 2 more answers