Answer:
Step 1:
To find ordered pair solutions, you could create an x and y graph and fill out the x side. Then, plug in an x number to get your y number and graph the ordered pairs to see if they give you a straight line. I'm going to use these numbers: -1, 0, 1, and 2.
![\left[\begin{array}{ccc}-1&?\\0&?\\1&?\\2&?\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26%3F%5C%5C0%26%3F%5C%5C1%26%3F%5C%5C2%26%3F%5Cend%7Barray%7D%5Cright%5D)
Now, let's plug in -1 into the equation first to see what we get for y.
-5 is our y if x was -1.
We do the same for the other three numbers.
Step 2:
With all that done, we can now fill out our table and graph the points.
![\left[\begin{array}{ccc}-1&-5\\0&3\\1&11\\2&19\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-5%5C%5C0%263%5C%5C1%2611%5C%5C2%2619%5Cend%7Barray%7D%5Cright%5D)
If you graph these points on graph paper / a graphing website, you will see that these points go in a straight line. If you are given an ordered pair already (for example: (3,5)), then all you have to do is plug in the x into the equation (3) and see if the outcome is true (5).
Since they don't equal each other, then (3,5) is false.
Here is the graph for the table above. I hope I helped you!
Answer:
b(t) = (t -5) (t+3) (t-2)
zero of the function is given by
b(t) = (t -5) (t+3) (t-2)=0
such that
(t -5) (t+3) (t-2)=0
i.e., (t -5)=0 and (t+3) =0 and (t-2)=0
consider (t -5)=0
t -5 =0
t+5-5=0+5
t=5
consider (t +3)=0
t +3 =0
t+3-3=0-3
t= -3
consider (t -2)=0
t -2 =0
t+2-2=0+2
t=2
answer is B
Step-by-step explanation:
The order order operations is "PEMDAS" Which means you would solve anything with in P: Parenthesis first, anything with E: exponents second, Do M:multiplication/D:division next, and leave A:addition/S:subtraction for last.
I hope this helps, but I need to know the equation or expression to the problem to walk you through it.
Question 1: Option B: 
Question 2: Option C: 
Solution:
Question 1:
Given ratio is 
.
To find the equivalent ratio of .
10 and 14 have the common factor 2.
So divide both numerator and denominator by the common factor 2.
Hence option B is the correct answer.
Question 2:
Given ratio is .
To find the equivalent ratio of 
.
12 and 18 have the common factor 3.
So divide both numerator and denominator by the common factor 3.
Hence option C is the correct answer.
Answer:
n=3.8416≅4
So Minimum Sample Size is 4
Step-by-step explanation:
In order to find the minimum sample size, the formula we use will be:
Where:
n is sample size
Z is the distribution
S is the standard deviation
E is the Margin of error
S=3 ,E=3
For Z:
Alpha=1-0.95=0.05
Alpha/2=0.025=2.5%
From Cumulative Standard Distribution Table:
Z at Alpha/2 = 1.960
n=3.8416≅4
So Minimum Sample Size is 4
