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Firdavs [7]
2 years ago
5

Determine the equation, in both factored and standard forms, of a parabola with zeros at (-2, 0) and (5, 0) and passes through t

he point (-1, -4)
Mathematics
1 answer:
Burka [1]2 years ago
3 0

The parabola equation in the factored and standard form are f(x) = (x + 2)(x - 5), and f(x) = (x - 3/2)² - 49/4 respectivly.

<h3>What is a parabola?</h3>

It is defined as the graph of a quadratic function that has something bowl-shaped.

We have:
Parabola with zeros at (-2, 0) and (5, 0) and passes through the point (-1, -4)

In factored forms:

f(x) = (x + 2)(x - 5)

Because zeros at (-2, 0) and (5, 0)

In the standard form:

f(x) = x² - 3x - 10 or

f(x) = (x - 3/2)² - 49/4

Thus, the parabola equation in the factored and standard form are f(x) = (x + 2)(x - 5), and f(x) = (x - 3/2)² - 49/4 respectivly.

Learn more about the parabola here:

brainly.com/question/8708520

#SPJ1

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Log 5 +3 log 2-log4÷log10<br>​
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●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Let's simplify step-by-step.

Log (5) + (3 log (2)) - \frac{log(4)}{log(10)}

= 0.69897 + 3(log (2)) - \frac{log (4)}{log (10)}

= 0.69897 + (3) (0.30103) - \frac{log (4)}{log(10)}

= 0.69897 + 0.90309 - \frac{log (4)}{log(10)}

= 1.60206 - \frac{log(4)}{log(10)}

= 1.60206 - \frac{1.60206}{log (10)}

= 1.60206 - \frac{1.60206}{1}

= 1.60206 - 0.60206

= 1

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●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Have a great day/night!

❀*May*❀

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Answer:

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Step-by-step explanation:

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