Please help me, I don't know this one.

1) Which equation could be used to estimate the population of Oak City in 10 years?

DaniilM [7]

Answer:

1) A

2) B

Step-by-step explanation:

For this problem we use exponential growth formulas

$y = y_0(1 + r) ^ t$ if the population increases when t increases

$y = y_0(1-r) ^ 2$ If the population decreases when t increases

Where and is the population as a function of time, $y_0$ is the initial population, r is the growth rate, t is the time in years.

1) In this situation we have that $y_0 = 48000$ , the growth is 2.4%, then $r = 0.024$ and $t = 10$ and the equation is:

$y = 48000(1 + 0.024) ^ {10}$

$y = 48000(1.024) ^ {10}$ -------- Option A)

2) In this situation we have that $y_0 = 82000$ , the decrease is 1.7%, then $r = 0.017$ and $t = 5$ and the equation is:

$y = 82000(1-0.017) ^ 5$

$y = 82000(0.983) ^ 5$ -------- Option B)

6 0

4 years ago

HELP! WILL GIVE BRAINLIEST!!! I think it's D please check

kow [346]

Answer:

(x + 5) (x^2 -3)

Step-by-step explanation:

$x^{3} +5x^{2} - 3x - 15$

Do the grouping:

$x^{3} +5x^{2} - 3x - 15 = (x^{3} +5x^{2}) + (-3x - 15)$

Then factor out $x^{2}$ in the first and −3 in the second group.

$x^{2}(x+5) - 3(x+5)$

Factor out the common term x + 5 by using the distributive property.

Polynomial $x^{2}-3$ is not factored in since it does not have any rational roots, thus getting the following:

$(x+5)(x^{2} -3)$

8 0

3 years ago

Read 2 more answers

A rectangular garden is enclosed with eighty-six meters of fencing. The garden is thirteen meters longer than it is wide. Find t

Sergio039 [100]

Answer: length = 28 meters

Width = 15 meters

Step-by-step explanation:

Let L represent the length of the rectangular garden.

Let W represent the width of the rectangular garden.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The rectangular garden is enclosed with eighty-six meters of fencing. This means that

2(L + W) = 86

Dividing through by 2, it becomes

L + W = 43- - - - - - - - - - - -1

The garden is thirteen meters longer than it is wide.. This means that

L = W + 13

Substituting L = W + 13 into equation 1, it becomes

W + 13 + W = 43

2W + 13 = 44

2W = 43 - 13

2W = 30

W = 30/2

W = 15

L = W + 13 = 15 + 13

L = 28

6 0

3 years ago

Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the

alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

There are 100 students
65 are members of a mathematics club
40 are members of a physics club
10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

#LearnwithBrainly

5 0

3 years ago

Pls helppp me with this

Annette [7]

Answer:

15

Step-by-step explanation:

Applying,

The angle bisector theorem of triangle

From the diagram,

Since ΔAMT is an issoceless triangle,

Then,

Line OA divides Line MT into two equal parts.

Therefore,

Line MO = Line OT.............. Equation 1

From the diagram,

Line MO = 4x-1, Line OT = 3x+3

Substitute into equation 1

4x-1 = 3x+3

Collect like terms

4x-3x = 3+1

x = 4.

Therefore,

OT = 3(4)+3

OT = 12+3

OT = 15

7 0

3 years ago