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Gekata [30.6K]
3 years ago
9

F(x) = - x2 + 2x; {–1, 2, 3}

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0
A is the correct answer just put the values from the domain and see for yourself
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In how many ways can five basketball players be placed in three positions?
Georgia [21]

Answer:

10 ways

Step-by-step explanation:

The number of ways in which five basketball players could be placed in three positions is:

5C_{3} = \frac{5!}{(5-3)!3!}

      = \frac{5!}{3!2!}

      = \frac{5*4*3*2!}{3*2*2!}

      = 5 × 2

     = 10

The basketball players can be arranged in 10 ways.

4 0
3 years ago
Y equals the quotient of the quantity x squared plus 4 times x and the quantity x cubed minus 5.
koban [17]

Given:

Consider the completer question is "Find the derivative \dfrac{dy}{dx} for y=\dfrac{x^2-4x}{x^3-5}."

To find:

The derivative \dfrac{dy}{dx}.

Solution:

Chain rule: \dfrac{d}{dx}f(g(x))=f'(g(x))\cdot g'(x)

Quotient rule: \dfrac{d}{dx}\dfrac{f(x)}{g(x)}=\dfrac{g(x)f'(x)-f(x)g'(x)}{[g(x)]^2}

We have,

y=\dfrac{x^2-4x}{x^3-5}

Differentiate with respect to x.

\dfrac{dy}{dx}=\dfrac{d}{dx}\left(\dfrac{x^2-4x}{x^3-5}\right)

Using chain rule and quotient rule, we get

\dfrac{dy}{dx}=\dfrac{(x^3-5)\dfrac{d}{dx}(x^2-4x)-(x^2-4x)\dfrac{d}{dx}(x^3-5)}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{(x^3-5)(2x-4)-(x^2-4x)(3x^2)}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{2x^4-4x^3-10x+20-3x^4+12x^3}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}

Therefore, the required answer is \dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}.

4 0
3 years ago
A restaurant has a total of 30 tables which are of two
Anna007 [38]

Answer:

Total number of tables of first type       = 23.

Total number of tables of second type = 7

Step-by-step explanation:

It is given that there are 30 tables in total and there are two types of tables.

Let's call the two seat tables, the first type as x and the second type as y.

∴                                             x + y = 30                        ......(1)

Also a total number of 81 people are seated. Therefore, 2x number of people would be seated on the the first type and 5y on the second type. Hence the equation becomes:

                                            2x + 5y = 81                        .....(2)

To solve (1) & (2) Multiply (1) by 2 and subtract, we get:

                                                      y = 7

Substituting y = 7 in (1), we get x = 23.

∴ The number of tables of first kind         = 23

  The number of tables of second kind   = 7

3 0
3 years ago
The cake store is having a 25%, percent off sale on all of its cakes. If the cake you want regularly costs $9 dollar , how much
Irina-Kira [14]
2.25 is how much you would save

7 0
3 years ago
Read 2 more answers
(THREE CAPITAL LETTERS FOR EACH) ANSWER CORRECTLY !!!!! WILL MARK BRIANLIEST !!!!!! URGENT !!!!!!!!!!
Natasha2012 [34]
FHG is congruent EFH
4 0
3 years ago
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