Answer:
Step-by-step explanation:
let : x The length and y the width you have this system :
xy =60....(1)
x = y+10...(2)
put the value for x in (1): (y+10)y =60
the quadratic equation is : y² +10y - 60 = 0
Δ =b² - 4ac a = 1 b= 10 c= - 60
Δ =10² - 4(1)(-60) = 324 =18²
y 1 = (-10-18)/2 negatif...... refused
y 2 = (-10+18)/2 =4
the width is 4
The first question would be distance from the start, as it is steadily going up as time goes on.
The second question would be distance from the end, as it is steadily going down as time goes on.
The third question would be speed, as the speed is staying stable as shown by the straight lines seen within the distance from start/end graphs being linear lines.
