The calculation uses the accumulated daily balance method (ADB).
We assume the statement is based on calendar month (rare!).
George owes $500 from beginning to end of June, so 30 days out of 30.
Interest accrued is 500*0.013*30/30=$6.50.
He also owes $2000 from June 12 to June 30, so 19 days inclusively.
Interest accrued is $2000*.013*(19/30)=16.47
Total interest at the end of the month=$6.50+$16.47=$22.97
We need to convert this equation to slope-intercept form first.
We can do that by solving for y.
x - 5y = 15
<em><u>Add 5y to both sides.</u></em>
x = 5y + 15
<em><u>Subtract 15 from both sides.</u></em>
x - 15 = 5y
<em><u>Divide both sides by 5.</u></em>
y = 1/5x - 3
We now know the slope is 1/5.
The slope of the line perpendicular to the line with a slope of 1/5 is -5.
The slope of a perpendicular line is the negative reciprocal of the original slope.
Using a graphing calculator, we know the y-intercept of the line that is perpendicular to the original line must have a y-intercept of -6 to run through the points (-2, 5).
The equation of the new line is y = -5x - 6.
Answer:
326.6
Step-by-step explanation:
I also need help on this question. Someone please help out
<h2>
Answer:</h2>
Our functions are:

To solve this, we must use the expression g(-10) - f(3).
![-\frac{3}{2}(-10) + 12 - [-5(3)] + 12\\\\15 + 12 - [-5(3)] + 12\\\\15 + 12 - (-15) + 12\\\\27 - (-15) + 12\\\\42 + 12\\\\54](https://tex.z-dn.net/?f=-%5Cfrac%7B3%7D%7B2%7D%28-10%29%20%2B%2012%20-%20%5B-5%283%29%5D%20%2B%2012%5C%5C%5C%5C15%20%2B%2012%20-%20%5B-5%283%29%5D%20%2B%2012%5C%5C%5C%5C15%20%2B%2012%20-%20%28-15%29%20%2B%2012%5C%5C%5C%5C27%20-%20%28-15%29%20%2B%2012%5C%5C%5C%5C42%20%2B%2012%5C%5C%5C%5C54)
The value of the expression g(-10) - f(3) is <em>15</em>.