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asambeis [7]
3 years ago
6

D%205" id="TexFormula1" title="3x + y = 1 \\ {x}^{2} + {y}^{2} = 5" alt="3x + y = 1 \\ {x}^{2} + {y}^{2} = 5" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Vinil7 [7]3 years ago
5 0

x =  -  \frac{2}{5} , \: y =  \frac{11}{5}  \\ x = 1, \: y =  - 2
You might be interested in
Jessica had $150 in her savings account after her first week of work. She then started adding $35 each week to her account for t
Natali [406]

M= money in her account

X = amount of weeks


M= $150 + $35x


M= $150 + $35(5)

5 0
3 years ago
Let π denote some population proportion of interest and suppose a 99% confidence interval for π is calculated to be (0.60, 0.70)
scZoUnD [109]

Answer:

The corresponding p-value will be smaller than 0.01.

Step-by-step explanation:

See attached picture for explanation.

3 0
3 years ago
Ben has ran for president of his class if there are 400 and 10 students and he received 72% of the vote. How many students were
blagie [28]

Answer:

287

Step-by-step explanation:

400+10=410

(70:100)*410

(70*410):100

28700:100 = 287

6 0
3 years ago
Iodine-131 has a half life of about 8 days. About how much is left from a 50 gram sample after 24 days?
andreyandreev [35.5K]
From the information given, we can see that the mass of Iodine-131 halves about every 8 days. There are 3 sets of 8 days in 24 days, so we will need to halve the mass of the sample 3 times:
50÷2=25
25÷2=12.5
12.5÷2=6.25
So after 24 days, the Iodine-131 sample will be 6.25g.
Here's a formula to figure this out, when dealing with bigger numbers:
a = i \times ({ \frac{1}{2} })^{ \frac{t}{h} }
Where
a = final amount
i = initial amount
1/2 is used because we are dealing with half lifes
t = time
h = half life of the isotope
8 0
3 years ago
Find the missing number of each unit rate. 2/4=1/? 2/6=1/? 4/12=1/? 8/24 =1/?
svlad2 [7]
2/4 = 1/2

2/6 = 1/3

4/12 = 1/3

8/24 = 1/3

If you need help on how to solve these, you can contact me directly
3 0
4 years ago
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