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3 years ago

A pair of dice are rolled. What is the probability of rolling 6 or less?

Mathematics

1 answer:

Allushta [10]3 years ago

6 0

Answer:

1/36

Step-by-step explanation:

The probability of rolling a number less than 6 or 6 itself on one die is 1/6. A pair of dice would be the combined probability 1/6*1/6 which is 1/36. So there's a 1/36 chance of having both dice roll numbers less than 6 or 6 itself.

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Find the quotient 5/18 divided by 2/6

Gnesinka [82]

5/18 diveded by 2/6 is 5/18*6/2 then its 5/18 * 3 which gives 15/18 or 5/6

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3 years ago

Daniel started a video game with 30 tokens. He earned 8 more tokens 0/10

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Step2247 [10]

Answer:

$A = 297\pi$

Step-by-step explanation:

To solve this problem we need to be familiar with the formula for the surface area of a cone:

$A = \pi r(r + \sqrt{h^2+r^2})$

We are given the length of a side and the diameter, to calculate the radius divide the diameter in half:

$r = \frac{d}{2}\\r = \frac{18}{2}\\r = 9 cm$

To calculate the height of the cone, we must use the Pythagorean Theorem:

$C^2 = A^2 + B^2$

We can treat the side length as the hypotenuse $C$ , the radius as the base $A$ , and solve for height $B$ . Set the expression up like this:

$C^2 = A^2 + B^2\\24^2 = 9^2 + B^2\\B^2 = 24^2 - 9^2\\B = \sqrt{24^2 - 9^2}\\B = \sqrt{576 - 81}\\B = \sqrt{495}\\B \approx 22.25$

Now we can plug into our original formula:

$A = \pi r(r + \sqrt{h^2+r^2})\\A = \pi 9(9+\sqrt{\sqrt{495}^2+9^2}\\A = \pi 9(9+\sqrt{495 + 81}\\A = \pi 9(9+\sqrt{576})\\A = \pi 9(9 + 24)\\A = \pi 9(33)\\A = 297\pi$

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2 years ago

If f(x) = 2x2 + 2, find f(5).

nalin [4]

answer for this question 22 if f(5)

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3 years ago