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ExtremeBDS [4]
2 years ago
8

A number that is the product of a number and a counting number is called a

Mathematics
1 answer:
Dmitrij [34]2 years ago
3 0

Answer: A multiple of a number is the product of the number and a counting number. So a multiple of 3 would be the product of a counting number and 3 .

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Find the value of x<br><br> 8th weekly math homework-week 29
Verdich [7]
Since the other angle that right next to it, the same angle you equal both angles together.

4x = 68.

We want to get x by its self. There is a 4 with the x and they're multiplying. to get rid of 4 we need to the opposite of multiplying which is division on both sides of the equation.

4x = 68
/4      /4

4 divided by 4 is 1 and 68 divided by 4 is 17

x = 17 is the answer.
If you plug in x = 17 into 4x, it will be 68

3 0
3 years ago
Read 2 more answers
What value makes x - 7 = -6 equation true?
Bumek [7]

Answer:

x=1

Step-by-step explanation:

In order to solve this equation, we must add 7 to each side. This gives us x=1

x-7=-6\\\\x=1

4 0
3 years ago
Please help! Correct answer only!
kykrilka [37]
55 - 3 = 52
52 - 3 = 49
49 - 3 = 46
46 - 3 = 43
43 is your answer
7 0
3 years ago
Variable y varies directly with variable x, and y = 45 when x = 9.
Alenkasestr [34]
Direct variation means their ratio is a constant
x/y is 9/45=1/5
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4 0
3 years ago
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
3 years ago
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