The correct answer to where the point(1, StartRoot 7 EndRoot) lies on the circle is A. Yes, the distance from (–2, 0) to (1, StartRoot 7 EndRoot) is 4 units
<h3>What is a Coordinate Plane?</h3>
This refers to the tool that is used to graph points on a two-dimensional plane that intersects two number lines.
Hence, given the information in the given diagram, there is a coordinate plane that shows a circle at the center that has certain values on the y and x-axis.
We can state that the point (1, StartRoot 7 EndRoot) lies on the circle shown because the distance from (–2, 0) to (1, StartRoot 7 EndRoot) is 4 units.
Read more about coordinate planes here:
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Answer:
B
Step-by-step explanation:
Using the Sine Rule in ΔABC
= 
= 
∠C = 180° - (82 + 58)° = 180° - 140° = 40°
Completing values in the above formula gives
= 
= 
We require a pair of ratios which contain b and 3 known quantities, that is
=
OR
= 
→ B
Step-by-step explanation:
It is easy
You can do by calculater
<h3>
Answer: n = -11</h3>
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Explanation:
Since x-2 is a factor of f(x), this means f(2) = 0.
More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
So if we plugged x = 2 into f(x), we'd get
f(x) = x^3+x^2+nx+10
f(2) = 2^3+2^2+n(2)+10
f(2) = 8+4+2n+10
f(2) = 2n+22
Set this equal to 0 and solve for n
2n+22 = 0
2n = -22
n = -22/2
n = -11 is the answer
Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10
Plug x = 2 into that updated f(x) function to find....
f(x) = x^3+x^2-11x+10
f(2) = 2^3+2^2-11(2)+10
f(2) = 8+4-22+10
f(2) = 0
Which confirms our answer.
