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fredd [130]
3 years ago
15

Guys what is the Radius of 15 feet????

Mathematics
2 answers:
PtichkaEL [24]3 years ago
6 0
The radius of 15 feet is 7.5 feet because you divde 15 by 2 and get your answer which is 7.5
Elenna [48]3 years ago
6 0
The answer is 7.5


Hope this helps
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Can someone please help me with this (it says I have to choose more than 1 answers)
Brrunno [24]

Answer:

B & C

Step-by-step explanation:

Since x is greater than 38, 40 and 120 matches the condition.

Hope u understand.

Please mark as the brainliest

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2 years ago
Find the measure of the third angle of a triangle given the measures of two angles.<br> 34 and 88
romanna [79]

Answer:

58

Step-by-step explanation:

All three angles of a triangle have to add up to 180. Given this we can do the following problem:

180-34-88 = 58

3 0
3 years ago
I need the answer ASAP please help
Fantom [35]

Answer:

5 and 50

Step-by-step explanation:

Constant of proportionality=(10-5)/(2-1)=5

Distance is 5*10=50

5 0
2 years ago
The _____ in the hundreds place has a value ____ times as great as the _____ in the _____ place. 440
solong [7]

Answer:

The 4 in the hundreds place has a value 10 times as great as the 4 in the tens place.

Step-by-step explanation:

440 = 400 + 40 + 0

the hundreds place is worth 400 here

it is worth 10x the tens place (40 here)

5 0
2 years ago
The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

AV = \frac{y(t2) - y(t1)}{t2 - t1}

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0
3 years ago
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