Answer:
6(3t+2)
Step-by-step explanation:
Answer:
[-5, 2]
Step-by-step explanation:
We have to find the interval for which f(x) <= 0, the interval is [-5, 2].
Solution
To solve this addition of fractions we are gonna apply the fraction rule which is;
a/c + b/c = (a + b)/c
2/11 + 1/11 = (2 + 1)/11
= (2 + 1)/11 + 2/7
Now add the numerators 2 + 1
= (2 + 1)/11 + 2/7
= 3/11 + 2/7
Now we find the least common multiple
The least common multiple of 11 and 7 is 77.
But before that we cross multiply the numerators.
3 * 7 = 21
2 * 11 = 22
Now the ajustes fraction is;
21/77 + 22/77
Apply the fraction rule which is;
a/c + b/c = (a + b)/c
= (21 + 22)/77
Now we add the numerators.
43/77
Therefore the answer in fraction is 43/77 and in decimal form it is 0.55841
<h2><u>✎ </u><u>
Answer:</u></h2>
<u />
➛➛➛➛➛
<h3>✂----------------</h3><h3>hope it helps...</h3><h3>have a great day!!</h3>
The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
