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Fed [463]
3 years ago
7

1. All of the following would be classified as manufacturing overhead except the: A) wages of supervisor of the machining shop.

B) depreciation of the equipment in the machining shop. C) property taxes relating to the building that houses the machining shop. D) All of the above would be classified as manufacturing overhead.
Business
1 answer:
jek_recluse [69]3 years ago
8 0

Answer:

D) All of the above would be classified as manufacturing overhead.

Explanation:

Manufacturing overhead is the overhead incurred directly in relation to the manufacturing process.

It can be fixed as well as variable, there is no standard conclusion for the above on the basis of nature of overhead.

Machining shop is a part of manufacturing process, and all expense related to that will be classified as manufacturing overhead, whether the expense is in cash like supervisor salary, property taxes of building of machining shop, or non cash expense like depreciation.

Therefore, all the expenses will be included in manufacturing overhead.

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Using a steel framework with masonry sheathing, the _____________, designed by louis sullivan, is thought by many to be the firs
xxTIMURxx [149]

wainwright building

7 0
3 years ago
Write the AddressList method newBusiness. This method searches addresses for an existing business with an identical address (i.e
max2010maxim [7]

Answer:

See explaination

Explanation:

// Address.java

public class Address {

/**

* The name of the business

*/

private String name;

/**

* The name of the street the business is on

*/

private String street;

/**

* The street number of the business

*/

private int number;

/**

* Constructs an Address that represents a business with name nm,

* at number no on the street st

*/

public Address(String nm, String st, int no)

{

name = nm;

street = st;

number = no;

}

/**

* Returns the name of the business

*/

public String getName()

{

return name;

}

/**

* Returns the name of the street on which the business is located

*/

public String getStreet()

{

return street;

}

/**

* Returns the street number of the business

*/

public int getNumber()

{

return number;

}

}

//end of Address.java

//AddressBook.java

import java.util.ArrayList;

import java.util.List;

public class AddressBook {

/**

* The list of business addresses. No two businesses in the list

* can have the same address (both the same street and street number)

*/

private List<Address> addresses;

/**

* Constructs an empty AddressBook

*/

public AddressBook()

{

addresses = new ArrayList<Address>();

}

/**

* atparam st the name of a street

* atreturn a list with the names of each business with an address on that street

*/

public List<String> onStreet(String st)

{

// create an empty output list of names of business

List<String> businessName = new ArrayList<String>();

// loop over the list of addresses

for(int i=0;i<addresses.size();i++)

{

// if ith street of address = nm, add the name of the business to the output list

if(addresses.get(i).getStreet().equalsIgnoreCase(st))

businessName.add(addresses.get(i).getName());

}

return businessName; // return the list

}

/**

* Searches for an existing business with an identical address (street and number

* both match). Updates the record to an address with name nm, street st and number no.

* If no entry already exists adds a new address to the end of the list with these parameters.

*

* atparam nm the name of the business

* atparam st the street the business is on

* atparam no the street number of the business

* atreturn the index of where the business address is on the list

*/

public int newBusiness(String nm, String st, int no)

{

// loop over the list of addresses

for(int i=0;i<addresses.size();i++)

{

// if ith index addresses match the street and number of the input st and no

if((addresses.get(i).getStreet().equalsIgnoreCase(st)) && (addresses.get(i).getNumber() == no))

{

addresses.remove(i); // remove the ith address from list

addresses.add(i, new Address(nm,st,no)); // add a new address with the input name, street and number at ith index

return i; // return the index i

}

}

// if no address match, add the business at the end of the list

addresses.add(new Address(nm,st,no));

return addresses.size()-1; // return the last index

}

}

//end of AddressBook.java

5 0
4 years ago
Item 1Item 1 Weismann Co. issued 11-year bonds a year ago at a coupon rate of 11 percent. The bonds make semiannual payments and
Mamont248 [21]

Answer:

Price of the bond is $940.

Explanation:

Price of bond is the present value of future cash flows. This Includes the present value of coupon payment and cash flow on maturity of the bond.

As per Given Data

As the payment are made semiannually, so all value are calculated on semiannual basis.

Coupon payment = 1000 x 11% = $110 annually = $55 semiannually

Number of Payments = n = 11 years x 2 = 22 periods

Yield to maturity = 12% annually = 6% semiannually

To calculate Price of the bond use following formula of Present value of annuity.

Price of the Bond = C x [ ( 1 - ( 1 + r )^-n ) / r ] + [ F / ( 1 + r )^n ]

Price of the Bond =$55 x [ ( 1 - ( 1 + 6% )^-22 ) / 6% ] + [ $1,000 / ( 1 + 6% )^22 ]

Price of the Bond = $55 x [ ( 1 - ( 1.06 )^-22 ) / 0.06 ] + [ $1,000 / ( 1.06 )^22 ]

Price of the Bond = $662.29 + $277.5

Price of the Bond = $939.79 = $940

8 0
3 years ago
Jameson Company uses average cost and a perpetual system. On January 1, the company had 600 units of inventory at an average cos
Leni [432]

Answer:

the average cost per unit that should be used to determine the cost of the units sold on January 28 is $ 59.00

Explanation:

The Weighted Average Cost Method calculates the new cost of Inventory with each purchase of Inventory.

The Perpetual Inventory System records the cost of inventory sold with each sale made.

<u>Calculation of  the new cost of Inventory with each purchase of Inventory :</u>

January 10:

Cost per Unit = Total Cost / Total Number of Units

Cost per Unit = (( 600 units × $55 per unit ) + ( 1000 units × $59 per unit )) / 1600 units

                      = $ 57.50

January 20:

Cost per Unit = Total Cost / Total Number of Units

Cost per Unit = (( 1600 units × $57.50 per unit ) + ( 800 units × $62 per unit )) / 2400 units

                      = $ 59.00

There were no further purchases from this point

Thus cost per units remains at $ 59.00

Therefore the average cost per unit that should be used to determine the cost of the units sold on January 28 is $ 59.00

3 0
3 years ago
Read 2 more answers
Mark Achin sells 3,600 electric motors each year. The cost of these is $200 each, and demand is constant throughout the year. Th
netineya [11]

Answer:

A) 100

Explanation:

total sales 3,600 units

cost per unit $200

cost of placing order $40

holding cost $20 per year

working days 360 per year

lead time 5 days

If Mark orders 200 units each time, his average inventory ?

daily sales = total sales / working days = 3,600 / 360 = 10 units per day

number of orders per year = 3,600 / 200 = 18

Mark places one order every = 360 days / 18 orders = 20 days

average inventory = (200 units / 20 days) x 10 days = 100

I assume that mark has some type of safety stock that allows him to hold enough inventory to cover for the 5 day lead time.

8 0
3 years ago
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