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Greeley [361]
3 years ago
7

Imagine a deck of 500 cards numbered from 1 to 500. If all the cards are shuffled randomly and you are asked to pick three cards

, one at a time, what's the probability of each subsequent card being larger than the previous drawn card
Mathematics
1 answer:
amm18123 years ago
6 0

Answer:

P = 1 / 6

Step-by-step explanation:

Given:-

- A deck has 500 cards

- Numbered from 1-500

Find:-

you are asked to pick three cards, one at a time, what's the probability of each subsequent card being larger than the previous drawn card

Solution:-

- Suppose we draw three cards. We don't care what they actually are, irrespective of number.

- Let the three numbers be a, b, c: Such that:

                                       a < b < c.

- The total possible combinations with 3 numbered cards will be:

                                       a b c

                                       b a c

                                       a c b

                                       b a c

                                       b c a

                                       c a b

- We have 6 possibilities for 3 numbered cards. So the probability of  of each subsequent card being larger than the previous drawn card would be:

                                     P = 1 / possible combinations

                                    P = 1 / 6

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v'(16)\approx\dfrac{v(20)-v(12)}{20-12}=\dfrac{240-200}8=5

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The Riemann sum approximates the integral as

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3 years ago
Need help ASAP I don’t understand what to do because x = 2 and y = 3 but they don’t divide into each other evenly so is it a dec
Artyom0805 [142]

Answer:

You can have it as a decimal (0.6 repeatings), or you can have it as a fraction. It would be easier to keep it as a fraction.

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2 years ago
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