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aleksklad [387]
3 years ago
15

Previous

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

just realized this is an old question

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Will (-2)^2 and -2^2 have the same solution? why or why not
nexus9112 [7]
Doing this so I can ask sorry
5 0
3 years ago
On March 24, 1989, the Exxon Valdez oil tanker ran aground and leaked millions of gallons of oil into Prince William Sound. The
Tema [17]

Answer:

592 hours

Step-by-step explanation:

Given

Area = 11000m^2

Radius = 0.10m/h

Required

Determine the time taken to cover the area

Since, the oil formed a circular pattern; the question will be answered using area of a circle

Area = \pi r^2

Let t represent the time take to cover 11000m²;

The relationship between these parameters is:

11000 = \pi * (0.10t)^2

Substitute 3.14 for π

11000 = 3.14 * (0.10t)^2

Divide both sides by 3.14

\frac{11000}{3.14} = \frac{3.14 * (0.10t)^2}{3.14}

\frac{11000}{3.14} =(0.10t)^2

3503.18471338 = (0.10t)^2

Take square root of both sides

\sqrt{3503.18471338} = \sqrt{(0.10t)^2}

\sqrt{3503.18471338} = 0.10t

59.1877074516 = 0.10t

Divide both sides by 0.10

\frac{59.1877074516}{0.10} = \frac{0.10t}{0.10}

\frac{59.1877074516}{0.10} = t

591.877074516 = t

t = 591.877074516

t = 592\ hours <em>(</em><em>Approximated)</em>

<em>Hence, it'll take approximately 592 hours to cover the given area</em>

3 0
3 years ago
Read 2 more answers
Can someone help me with this question
shtirl [24]
I believe its 5 shirts
4 0
3 years ago
A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
Someone please help!!
Bumek [7]

Answer:

I believe the answer would be option D

Step-by-step explanation:

the distance formula is

\sqrt{(x - x1)^{2} + (y - y1)^{2}  }

So, substituting the values of the coordinates, you will get the answer of D

4 0
1 year ago
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