Answer:
<em>2(∛6 ) </em>
Step-by-step explanation:
∛12 × ∛ 4 = = ∛48 = = <em>2(∛6 )</em>
1.g(f(x)) = g(x^3 - 27)(x)
=x^3 - 27 -3
=x^3 -30
Matched with letter A.
2.f(x^2(x))= (x^3 - 27)^2
=(x^3 - 27)(x^3 - 27)
=x^6 - 54x^3 + 729
Matched with letter C
3. f(g(x))= f(x - 3)(x)
=(x - 3)^3 - 27
=[(x - 3)(x - 3)(x - 3)]-27
=x^3- 9^2+ 27x- 54
Matched with letter B.
4. (f(x))2 = (x^3 - 27)^2
=(x^3 - 27)(x^3 - 27)
=x^6 - 54x^3 + 729
Matched with letter C
First term: -9
Common difference: 7
a(n) = -9 + 7(n-1), for n = {1, 2, 3, ... }
Check: what is the first term? let n=1. Then a(1) = -9 + 7(1-1) = -9.
This is correct.
Answer:
a number that is divisible only by itself and 1 (e.g. 2, 3, 5, 7, 11).
Step-by-step explanation:
Lets write the problem info into an equation and solve step by step:
7(1/3 + 4/5)
the minimum common multiple of 3 and 5 is 15, so we multiply and divide the fractions by a proper number to convert them to be divided by 15 so is easier to add them:
<span>(1/3)(5/5) = (1*5)/(3*5) = 5/15
(4/5)(3/3) = (4*3)/(5*3) = 12/15
</span>so we substitute in the original equation:
7(1/3 + 4/5<span>)
</span>= 7(5/15 + 12/15<span>)
= 7(17/15)
= (7*17)/15
= 119/15</span>