1 year ago

I need help with solving a system of equations using elimination

Mathematics

1 answer:

Nataliya [291]1 year ago

7 0

Answer:

do it your self.

Step-by-step explanation:

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Can someone help me fast I need to get this to a 90 I have it at 80 rn

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-1/2 is the slope of the line!

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2 years ago

Seni has a goal to save $500. So far he has saved $340.50 . How much more does he need to save to reach his goal?

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Step-by-step explanation:

500 − 340.5 =159.50

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Amanda is building a dollhouse that is a model of her real house with a scale factor of 1/20. In the real house, the kitchen mea

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Answer:

0.5 feet × 0.6 feet

Step-by-step explanation:

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2 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

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2 years ago

PLEASE HELP ME!!!!!!

Kisachek [45]

The answer to this is 9
hoped this helped

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2 years ago