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ololo11 [35]
2 years ago
15

M and m Please find quick

Mathematics
1 answer:
Lady_Fox [76]2 years ago
4 0

Answer:

wELL YOU WANT TO GRAB SOME M AND MS AND EAT THEM

Step-by-step explanation:

You might be interested in
What is the volume of the prism below? 12 in 16 in 9 in
Inga [223]

Answer:

1728 units cubed

Step-by-step explanation:

V = LWH
V = 12x16x9
V = 1728

5 0
2 years ago
A number rounded to the nearest ten is 550. When it is rounded to the nestest hundred,the number become 600 which could it ve?
amid [387]

Answer:

550-554

Step-by-step explanation:

550 is rounded to 550, and also rounded to 600. Same with all the other numbers. :)

8 0
3 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
2 years ago
Can u help me with this
erica [24]
The last one because it can be traced like Jerome gets these cards from this place but others from a different place
8 0
3 years ago
Read 2 more answers
5x + 3y = -2
tamaranim1 [39]

Answer:

x = -1 , y = 1

Step-by-step explanation:

Solve the following system:

{5 x + 3 y = -2 | (equation 1)

3 x + 2 y = -1 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x + 3 y = -2 | (equation 1)

0 x+y/5 = 1/5 | (equation 2)

Multiply equation 2 by 5:

{5 x + 3 y = -2 | (equation 1)

0 x+y = 1 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x+0 y = -5 | (equation 1)

0 x+y = 1 | (equation 2)

Divide equation 1 by 5:

{x+0 y = -1 | (equation 1)

0 x+y = 1 | (equation 2)

Collect results:

Answer: {x = -1 , y = 1

8 0
2 years ago
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