The function f(x) is represented by this table of values .Match average rate of change of f(x) with corresponding intervals

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

3 0

Note:
If fx(x) changes from f(x₁) to f(x₂), the rate of change is
Rate = [f(x₂) - f(x₁)]/(x₂ - x₁)

From the table, we can compute rates of change as follows:
Change in x Change in f(x) Change in x Rate
----------------- -------------------- ----------------- ---------
[-4,-2] 0 - (-12) = 12 0 - (-2) = 2 6
[-2, 1] 3 - 0 = 3 1 - (-2) = 3 1
[-3, 1] 3 - (-5) = 8 1 - (-3) = 4 2
[-4, 0] 4 - (-12) = 16 0 - (-4) = 4 4

You might be interested in

Suppose that the walking step lengths of adult males are normally distributed with a mean of 2.5 feet and a standard deviation o

Mumz [18]

Answer:

0% probability that the mean of the sample taken is less than 2.2 feet.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .