Tan⁴x - sec⁴x = 1 - 2sec²x
tan²x = sec²x - 1
tan⁴x - sec⁴x = 1 - 2sec²x
(tan²x)² - sec⁴x = 1 - 2sec²x
(sec²x - 1)² - sec⁴x = 1 - 2sec²x
(sec²x)² - 2 * sec²x + 1 - sec⁴x = 1 - 2sec²x
sec⁴x - 2 sec²x + 1 - sec⁴x = 1 - 2sec²x
sec⁴x can be cancelled:
- 2 sec²x + 1 = 1 - 2sec²x
1 - 2sec²x = 1 - 2sec²x
The answer is D . It increases by 35.25
Answer:
E = 96
Step-by-step explanation:
Given the following data;
E = kf .......equation 1.
When E = 24, f = 6
First of all, we would have to find the constant k;
Substituting the values into eqn 1, we have;
24 = k6
k = 24/6
k = 4
To find the value of E, when f = 24
E = kf
Substituting into the equation, we have;
E = 4*24
E = 96
The answer is 5.14 ur well come (instagram:2k15sgraduate_bish_where)