Ask question

Ask question

All categories

Juliette [100K]

3 years ago

10

A train traveled 720km in 9h. How far would it travel in 11 hr? How long would it take to go 1120km?

2 answers:

kompoz [17]3 years ago

6 0

It would go 880 km in 11 hours, and it would take 14 hours to go 1120 km

Ahat [919]3 years ago

3 0

How far would it travel in 11 hours?
First, we have to find how much the train travels in 1 hour. We are finding the unit rate. So, divide 720 by 9 and we get 80. The train travels 80 km in one hour. We have to find how much it travels in 11 hours. We multiply 80 by 11 and we get 880.
<u>The train would travel 880 km in 11 hours.</u>

How long would it take the train to travel 1,120 km?
Since we know that the train can travel 80 km per hour , we can divide 1,120 by 80. When we divide we get 14.
<u>The train would travel 1,120 km in 14 hours.</u>

-Hope this helped! :)

You might be interested in

0.005 write as a fraction

kirill115 [55]

0.005 would be 5/1000 because how I know if it is 10ths or 100ths or 1000ths I count all the number on the right side of the decimal, hoped this could help!

5 0

4 years ago

Read 2 more answers

Suppose that a person's peak blood alcohol level is 0.07 (grams per 100 mL) and that this level decreases by 40% each hour.

Natalija [7]

Answer:

Step-by-step explanation:

Considering a person peak blood is 0.07

It decrease by 4% every hour

a) Using exponential function

$f(x) = Ca^x$

where,

a = 1 + r

r = -0.40%

Here,

C = 0.07,

a = 1 - 0.04 = 0.06

$f(x)=0.07(0.6)^x$

<h3>Therefore, hourly decay factor is 0.6</h3>

b)

Here the hourly decay factor is 0.6

$B(x)=ca^x\\\\0.07(0.6)^x$

c) Evaluate

$B(2)=0.07\times (0.6)^2\\\\0.07(0.36)\\\\= 0.0252g$

0.0252g or 100mL

<h3>Thus, after 2 hours the blood is 0.0252g or 100mL</h3>

3 0

3 years ago

Read 2 more answers

Triangle XYZ has vertices X(2,4), Y(3,4) and Z(3,8). Suppose you reflect this across the y-axis, then dilate it with a scale fac

mel-nik [20]

Answer:

X'' (-4, 8)

Y'' (-6, 8)

Z'' (-6, 16)

Step-by-step explanation:

The rule for reflecting across the y-axis is (x, y) -> (-x, y)

When you dilate by a scale factor of 2 about the origin, multiply each coordinate point by 2.

X (2, 4) -> (-2, 4) -> (-4, 8)

Y (3, 4) -> (-3, 4) -> (-6, 8)

Z ( 3, 8) -> (-3, 8) -> (-6, 16)

7 0

3 years ago

18 cajas de manzanas y peras fueron llevadas a la escuela. Las peras trajeron 210 kg en 6 cajas. ¿Cuántos kilos de manzanas fuer

Katyanochek1 [597]

Answer:

504 kilos de manzanas fueron llevados a la escuela.

Step-by-step explanation:

Sean $x$ , $y$ la cantidad de cajas de manzanas y peras, respectivamente. De acuerdo con el enunciado, tenemos el siguiente sistema de ecuaciones:

Total de cajas

$x+y = 18$ (1)

Masa de cada caja de peras

$y\cdot m_{P} = 210$ (2)

$y = 6$ (3)

Masa de caja de manzanas

$m_{M} = m_{P}+7$ (4)

De (2) en (3), tenemos que la masa de cada caja de peras es:

$m_{P} = 35\,kg$

Por (4), encontramos que la masa de cada caja de manzanas es:

$m_{M} = 35\,kg+7\,kg$

$m_{M} = 42\,kg$

Finalmente, de (1) tenemos la cantidad de cajas de manzana:

$x = 18-y$

$x = 12$

La cantidad de kilos de manzanas llevada a la escuela se obtiene al multiplicar la cantidad de cajas de manzana por la masa de cada caja:

$M = (12)\cdot (42\,kg)$

$M = 504\,kg$

504 kilos de manzanas fueron llevados a la escuela.

7 0

3 years ago

2/4 plus 1/3 as a fraction

QveST [7]

Answer: 5/6

Step-by-step explanation: trust me on this

7 0

3 years ago

Read 2 more answers