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jeyben [28]
3 years ago
10

I need help on this 3,4,and 2 help me solve one please

Mathematics
1 answer:
Mrrafil [7]3 years ago
4 0

3) 12 divided by 3= 4

4 x 2= 8

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This is 8th grade math.
Mrrafil [7]
X = 1 , y = - 2


Hope this helped
4 0
2 years ago
Read 2 more answers
Ashlyn and Brooke went to the arcade with $12. They bought 4 bottles of water, which cost $1.50 each. They each bought a sticker
ANEK [815]

Answer:

not good in maths

Step-by-step explanation:

5 0
3 years ago
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Find the value of n in the equation 6.2n – 3.7n = 85 + 45. A. 16 B. 52 C. 13.13 D. 325
vesna_86 [32]
6.2n-3.7n=85+45
2.5n=130
N=130/2.5
N=52

The answer is B. Hope this helps!

7 0
4 years ago
Need legitimate math help and legitimate answers please
liraira [26]

Answer:

73626983

Step-by-step explanation:

there’s the answer DONT CLICK AND LINK ID SOMEONE SAY U CAN DOWNLOAD THE ANSWER THERE THEY WILL TRACK U

3 0
3 years ago
Read 2 more answers
Un aljibe de 12.4 m de profundidad se encuentra totalmente lleno de agua. ¿Cual es la presión en el fundo debido únicamente al p
Kamila [148]

Answer:

a) p = 121644 Pa

b) p_{T} = 221644 Pa  

Step-by-step explanation:

a) La presión en el fondo debido únicamente al peso del agua se puede calcular usando la siguiente ecuación:

p = \rho gh

En donde:

ρ: es la densidad del agua = 1000 kg/m³

g: es la gravedad = 9.81 m/s²

h: es la profundidad = 12.4 m

p = \rho gh = 1000 kg/m^{3}*9.81 m/s^{2}*12.4 m = 121644 Pa

Entonces, la presión en el fondo debido al agua es 121644 Pa.

b) Para hallar la presión total en el fondo debemos ahora considerar la presión atmosférica:

p_{T} = p_{0} + \rho gh  

En donde p₀ es la presión atomsférica = 75 cmHg

p_{T} = 750 mmHg\frac{1 Pa}{0.0075 mmHg} + 121644 Pa = 221644 Pa

Por lo tanto, la presión total en el fondo es 221644 Pa.

Espero que te sea de utilidad!

4 0
3 years ago
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