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madam [21]
3 years ago
8

I need to k ow how to do this

Mathematics
2 answers:
Kisachek [45]3 years ago
6 0
Put another paper on it and follow the line go over the same line if u need to
Ainat [17]3 years ago
3 0
You just need to trace it without moving your pencil off the paper
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What is orthogonal in linear algebra
o-na [289]
This is a square matrix whose entries are real and rows and columns are orthogonal unit vectors.
8 0
3 years ago
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Look at the pentagonal numbers. Use finite differences to determine which function represents the pattern.
Ahat [919]

Answer:

f(x) = 1.5x - 0.5x

Step-by-step explanation:

The function of the pattern represented by the pentagonal numbers is the sum of three triangular numbers.

The triangular number general formula

                      x (x + 1) / 2

For  example,

The sequence

1,     3,     6,      10

                                             *

                          *              *  *

         *           *   *          *   *  *

* ,    *  *,     *   *   *,     *   *   *  *

_____________________________

The pentagonal numbers

The sequence:

1, 5, 12, 22, 35

As shown in the picture can be divided into three triangles

Triangle 2

x (x + 1) / 2

Triangle 1 and 3  (they are triangles one unit smaller than 2)

n (n + 1) / 2

n= x-1

Replacing n

(x-1) ((x-1) + 1) / 2

(x-1) (x) / 2

(x-1) x / 2

______________

Function represents the pattern

Triangle 2  + (Triangle 1  +  Triangle 3)

Triangle 1  = Triangle 3

So then,

Triangle 2 + 2* Triangle 1

x (x +1) /2  + 2* (x -1) x/2

Rearranging

0.5 x (x +1) + x(x -1)

0.5x^2 + 0.5x + x^2 -x

(0.5 x^2 + x^2)  + (0.5x -x )

1.5 x^2 - 0.5 x  

______

3 0
3 years ago
Read 2 more answers
X^2 + Y^2 +ax + 2y + 3 = 0<br><br> What number is this equation the equation of a circle?
Sav [38]

Answer:

Eq: (x+a/2)²+(y+1)²=(a²-8)/4

Center: O(-a/2, -1)

Radius: r=0.5×sqrt(a²-8)

Mandatory: a>2×sqrt(2)

Step-by-step explanation:

The circle with center in O(xo,yo) and radius r has the equation:

(x-xo)²+(y-yo)²=r²

We have:

x²+y²+ax+2y+3=0

But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4

And

y²+2y+3=y²+2y+1+2=(y+1)²+2

Replacing, we get:

(x+a/2)²-a²/4+(y+1)²+2=0

(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4

By visual inspection we note that:

- center of circle: O(-a/2, -1)

- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)

6 0
3 years ago
Find the arc length of the partial circle. <br>length is 1.<br>**See attached photo**<br>​
KatRina [158]

Arc length of the quarter circle is 1.57 units.

Solution:

Radius of the quarter circle = 1

Center angle (θ) = 90°

To find the arc length of the quarter circle:

$\text{Arc length}=2 \pi r\left(\frac{\theta}{360^\circ}\right)

                 $=2 \times 3.14  \times 1\left(\frac{90^\circ}{360^\circ}\right)

                $=2 \times 3.14  \times 1\left(\frac{1}{4}\right)

Arc length = 1.57 units

Arc length of the quarter circle is 1.57 units.

5 0
3 years ago
What is the missing reason in the proof?
Helen [10]
A............zzzzzzzzzz
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3 years ago
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