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3 years ago

What 2/5×3/7 but, once you get an answer make sure you simplified

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

3 0

Answer:

6/35

Step-by-step explanation:

$\frac{2}{5} *\frac{3}{7} =\frac{2*3}{5*7} =\frac{6}{35}$

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Kelly was baking bread but could only find her 1/8 cup measuring cup. She needs 1/4 cup sugar,3/4 cup whole wheat flour, and 1/2

irga5000 [103]

Answer:

Step-by-step explanation:

cups

for sugar=1/4÷1/8=1/4×8=2

whole wheat flour=3/4÷1/8=3/4×8=6

all purpose flour=1/2÷1/8=1/2×8=4

6 0

4 years ago

Molly has $45 in her wallet, which is 3 times as much as her brother has

Anna007 [38]

Answer:$15

Step-by-step explanation:

45 divided by 3 =15

8 0

3 years ago

Read 2 more answers

Dafna11 [192]

The approximate length of rail that needs to be replaced is 7.1 ft

<h3>Length of arc</h3>

Since the pool is circular, the approximate length that needs to be replaced is an arc of length, L = Ф/360° × πD where

Ф = central angle of rail section = 27° and
D = diameter of circular pool = 30 ft

<h3>Approximate length of rail</h3>

So, substituting the values of the variables into the equation, we have

L = Ф/360° × πD

L = 27°/360° × π × 30 ft

L = 3/40 × π × 30 ft

L = 3/4 × π × 3 ft

L = 9/4 × π ft

L = 2.25 × π ft

L = 7.07 ft

L ≅ 7.1 ft

So, the approximate length of rail that needs to be replaced is 7.1 ft

Learn more about length of an arc here:

brainly.com/question/8402454

5 0

2 years ago

A = 4 0 0 1 3 0 −2 3 −1 Find the characteristic polynomial for the matrix A. (Write your answer in terms of λ.) Find the real ei

Illusion [34]

Answer:

Step-by-step explanation:

We are given the matrix

$A = \left[\begin{matrix}4&0&0 \\ 1&3&0 \\-2&3&-1 \end{matrix}\right]$

a) To find the characteristic polynomial we calculate $\text{det}(A-\lambda I)=0$ where I is the identity matrix of appropiate size. in this case the characteristic polynomial is

$\left|\begin{matrix}4-\lambda&0&0 \\ 1&3-\lambda&0 \\-2&3&-1-\lambda \end{matrix}\right|=0$

Since this matrix is upper triangular, its determinant is the multiplication of the diagonal entries, that is

$(4-\lambda)(3-\lambda)(-1-\lambda)=(\lambda-4)(\lambda-3)(\lambda+1)=0$

which is the characteristic polynomial of A.

b) To find the eigenvalues of A, we find the roots of the characteristic polynomials. In this case they are $\lambda=4,3,-1$

c) To find the base associated to the eigenvalue lambda, we replace the value of lambda in the expression $A-\lambda I$ and solve the system $(A-\lambda I)x =0$ by finding a base for its solution space. We will show this process for one value of lambda and give the solution for the other cases.

Consider $\lambda = 4$ . We get the matrix

$\left[\begin{matrix}0&0&0 \\ 1&-1&0 \\-2&3&-5 \end{matrix}\right]$

The second line gives us the equation x-y =0. Which implies that x=y. The third line gives us the equation -2x+3y-5z=0. Since x=y, it becomes y-5z =0. This implies that y = 5z. So, combining this equations, the solution of the homogeneus system is given by

$(x,y,z) = (5z,5z,z) = z(5,5,1)$