Circumference of the smaller circle, using
![C = \pi d](https://tex.z-dn.net/?f=C%20%3D%20%5Cpi%20d)
, is approximately equal to 18.85 (I used the high floating point precision approximation of pi my calculator has in memory, then rounded to 2 decimal points.)
Using the formula
![S = 0.2L](https://tex.z-dn.net/?f=S%20%3D%200.2L)
, which in English says "the smaller circle's circumference is equal to 20% of the larger circle's", we can substitute the known value S:
![18.85 = 0.2L](https://tex.z-dn.net/?f=18.85%20%3D%200.2L)
and solve for L:
![\frac{18.5}{0.2} = L, L = 92.5](https://tex.z-dn.net/?f=%20%5Cfrac%7B18.5%7D%7B0.2%7D%20%3D%20L%2C%20L%20%3D%2092.5)
.
So the larger circle has a circumference approximately equal to 92.5 units.
Answer:
1.28
2. -3.5
3.-10.5
Step-by-step explanation:
1.-0.0035 · 12000+70= 28
2. -0.0035 ·21000+70=-3.5
3. -0.0035 ·23000+70=-10.5
I hope this helps
I think its saying find a side that has no numbers or has a letters. figure out the whole shape then subtract the sides we do know and theres your answer. And if its a decimal round the decimal to the nearest tenth
![\frac{15.6}{100} ](https://tex.z-dn.net/?f=%20%5Cfrac%7B15.6%7D%7B100%7D%20%0A)
← multiply both the numerator and the denominator by 10
![\frac{156}{1000}](https://tex.z-dn.net/?f=%20%5Cfrac%7B156%7D%7B1000%7D%20)
<span>← simplify
</span>
![\frac{39}{250}](https://tex.z-dn.net/?f=%5Cfrac%7B39%7D%7B250%7D)
The answer's
![\frac{39}{250}](https://tex.z-dn.net/?f=%5Cfrac%7B39%7D%7B250%7D)
.