Answer:
The height of the tree=8.42 m
Step-by-step explanation:
We are given that
Height of Joshua, h=1.45 m
Length of tree's shadow, L=31.65 m
Distance between tree and Joshua=26.2 m
We have to find the height of the tree.
BC=26.2 m
BD=31.65m
CD=BD-BC
CD=31.65-26.2=5.45 m
EC=1.45 m
All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.
Substitute the values
Hence, the height of the tree=8.42 m
The answer is 6200
i think
your welcome
It is already in standard form.
Answer:
v = 9/2 + sqrt(61)/2 or v = 9/2 - sqrt(61)/2
Step-by-step explanation:
Solve for v over the real numbers:
-v^2 + 9 v - 5 = 0
Multiply both sides by -1:
v^2 - 9 v + 5 = 0
Subtract 5 from both sides:
v^2 - 9 v = -5
Add 81/4 to both sides:
v^2 - 9 v + 81/4 = 61/4
Write the left hand side as a square:
(v - 9/2)^2 = 61/4
Take the square root of both sides:
v - 9/2 = sqrt(61)/2 or v - 9/2 = -sqrt(61)/2
Add 9/2 to both sides:
v = 9/2 + sqrt(61)/2 or v - 9/2 = -sqrt(61)/2
Add 9/2 to both sides:
Answer: v = 9/2 + sqrt(61)/2 or v = 9/2 - sqrt(61)/2
