1 answer:
Area of the three equally sized stripes: A A=(x+15)(x)(3) A=3x(x+15) A=3x^2+45x One gallon of paint will cover an area of no more than 400 square feet: <=400 She only has half of a gallon of paint left: 1/2(400 square feet)=400/2=200 square feet Inequality that could be used to find the maximum height, in feet, of each stripe: A<=200 3x^2+45x<=200 Answer: 3x^2+45x <= 200 Could her stripes be 3' tall? x=3→A=3(3)^2+45(3)=3(9)+135=27+135→A=162<200 Ok Yes, her stripes could be 3' tall. Answer: Yes Could her stripes be 4' tall? x=4→A=3(4)^2+45(4)=3(16)+180=48+180→A=228>200 No No, her stripes couldn't be 4' tall. Answer: No
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