Answer:
(- 2, 4 )
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
y - 4 = - 3(x + 2) ← is in point- slope form
with (a, b ) = (- 2, 4 )
Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.



Subtract 16 from both sides.


Divide by 4 on both sides.


The length of line segment PQ is 5 units.
There you go? Is that right or no?