"Complementary" angles sum to 90°.
Since we are using minutes as well...
80°+d°+25'+m'=90° subtract 80° from both sides
d°+25'+m'=10° subtract 25' from both sides
d°+m'=9°+60'-25'
d°+m'=9°+35'
9°35'
Answer:
What is that
Step-by-step explanation:
Answer:
the vertices are all labeled
a b c d and e
Answer:
C) 
Step-by-step explanation:
Use the Angle Addition Postulate to figure this out:
165° = (x + 15)° + (9x)°
165° = (15 + 10x)°
- 15° - 15°
_____________
![\displaystyle \frac{150°}{10} = \frac{[10x]°}{10} \\ \\](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B150%C2%B0%7D%7B10%7D%20%3D%20%5Cfrac%7B%5B10x%5D%C2%B0%7D%7B10%7D%20%5C%5C%20%5C%5C)
[Plug this back into the modeled expression for the 
to get the angle measure of 30°]; 
I am joyous to assist you anytime.
Answer:
x = friends that paid discount price = 8
y = friends that paid regular price = 4
Step-by-step explanation:
Let
x = friends that paid discount price
y = friends that paid regular price
x + y = 12 (1)
6x + 8y = 80 (2)
From (1)
x = 12 - y
Substitute x = 12 - y into (2)
6x + 8y = 80 (2)
6(12 - y) + 8y = 80
72 - 6y + 8y = 80
- 6y + 8y = 80 - 72
2y = 8
y = 8/2
y = 4
Substitute y = 4 into (1)
x + y = 12 (1)
x + 4 = 12
x = 12 - 4
x = 8
x = friends that paid discount price = 8
y = friends that paid regular price = 4
