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NISA [10]
4 years ago
5

If the midpoint between (x, 6) and (-9, 14) is (8, 10), find the value of x

Mathematics
2 answers:
Romashka-Z-Leto [24]4 years ago
8 0
Mid point is found by summation of x
Then divide by 2
And same for y

Since mid point for x is 8
So x+(-9) /2 = 8
X - 9 = 16
X=16+9
X= 25
zmey [24]4 years ago
4 0

Answer:

<h3>the value of x is 25.</h3>

Step-by-step explanation:

Givens

  • The midpoint is between (x,6) and (-9,14).
  • The midpoint is at (8,10).

Now, the formula of a midpoint is

M=(\frac{x_{1} +x_{2} }{2} ,\frac{y_{1}+y_{2}  }{2} )

Where M=(8,10)

This means that

\frac{x_{1} +x_{2} }{2}=8\\ \frac{y_{1} +y_{2} }{2}=10

Replacing each horizontal coordinate and solving for x

\frac{x +(-9) }{2}=8\\x-9=16\\x=16+9\\x=25

Therefore, the value of x is 25.

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Step-by-step explanation:

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Then subtract 177.8/178 from 267 to find the amount of seats not being used.

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I hope this helps!

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Read 2 more answers
A square has a a side lenght of 5 feet what is its area?
goldenfox [79]

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25 sq feet

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7 0
3 years ago
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
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