The graph shows the the number of jars that are filled by machine A and machine B. Which statement is true about the unit rates
shown in the graph?
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The unit rate for machine A is greater because the slope is greater than the slope for machine B.
The unit rate for machine B is greater because the slope is less than the slope for machine A.
The unit rate for machine A is greater because the slope is less than the slope for
machine B.
The unit rate for machine B is greater because the slope is greater than the slope for machine A.
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The unit rate for machine A is greater because the slope is greater than the slope for machine B.
The unit rate for machine B is greater because the slope is less than the slope for machine A.
The unit rate for machine A is greater because the slope is less than the slope for
machine B.
The unit rate for machine B is greater because the slope is greater than the slope for machine A.
2 answers:
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Answer:
The rocket will reach its maximum height after 6.13 seconds
Step-by-step explanation:
To find the time of the maximum height of the rocket differentiate the equation of the height with respect to the time and then equate the differentiation by 0 to find the time of the maximum height
∵ y is the height of the rocket after launch, x seconds
∵ y = -16x² + 196x + 126
- Differentiate y with respect to x
∴ y' = -16(2)x + 196
∴ y' = -32x + 196
- Equate y' by 0
∴ 0 = -32x + 196
- Add 32x to both sides
∴ 32x = 196
- Divide both sides by 32
∴ x = 6.125 seconds
- Round it to the nearest hundredth
∴ x = 6.13 seconds
∴ The rocket will reach its maximum height after 6.13 seconds
There is another solution you can find the vertex point (h , k) of the graph of the quadratic equation y = ax² + bx + c, where h = and k is the value of y at x = h and k is the maximum/minimum value
∵ a = -16 , b = 196
∴
∴ h = 6.125
∵ h is the value of x at the maximum height
∴ x = 6.125 seconds
- Round it to the nearest hundredth
∴ x = 6.13 seconds
Answer: 2z-15
Step-by-step explanation
Based on the visual image, AD is a line where a point O intersects somewhere on the line. AD is represented as 3z-11, while the segment from AO is represented as z+4.
In order to find the answer, we must subtract the entire line (AD) from AO in order to find the missing segment OD.
AD - AO = OD
(3z-11) - (z+4) = OD
Distribute the negative sign so it becomes:
(3z-11) -z - 4 = OD
Now combine like terms.
(3z-z) +(- 11 -4)= OD
2z - 15 = OD
And that is your answer!
Since there is no picture shown, I just plotted the given data points myself. That is shown in the attached picture. The blue rectangle is rectangle PQRS while the orange one is rectangle JKLM. I believe there are some choices for this question but you forgot to include. Nevertheless, I will give my observations from the given figure.
The tile PQRS is bigger than tile JKLM. A rectangle is a two-dimensional shape that has two sets of equal parallel planes. Thus, its area is equal to the length multiplied by its width.
tile PQRS = (9-5)*(12-7) = 20 units²
tile JKLM = (6-4)*(10-5) = 10 units²
Tile PQRS is larger by 10 units².
The tile PQRS is bigger than tile JKLM. A rectangle is a two-dimensional shape that has two sets of equal parallel planes. Thus, its area is equal to the length multiplied by its width.
tile PQRS = (9-5)*(12-7) = 20 units²
tile JKLM = (6-4)*(10-5) = 10 units²
Tile PQRS is larger by 10 units².