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Neporo4naja [7]
3 years ago
9

The ratio of blue to yellow is 4:5 and there are 15 yellow how many blue is there?

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer: 12 blue marbles

Step-by-step explanation: Set up a proportion.

4/5 = x/15

Solve for x, the number of blue marbles. Cross multiply. You will get 60 = 5x

Divide by 5 on each side.

x = 12

There are 12 blue marbles.

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The solution to a system of equations is the point that the 2 lines of the graph cross each other.

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3 years ago
Solve 8x+2y=13 and 4x+y=11 using substitution
Aleonysh [2.5K]

Answer:

No Solution

Step-by-step explanation:

8x+2y=13                         4x+y=11               Subtract 4x on both sides to isolate y

                                        y=-4x+11       <---- Substitute this equation into the                                            

                                                                     equation 8x+2y=13

8x+2(-4x+11)=13

8x-8x+22=13

22=13 (not true)

No Solution          

                     

4 0
3 years ago
Please help me please
balu736 [363]

Answer:

Step-by-step explanation:

2n + 8.5 = 23

2n = 14.5

2n = 7.25 or 7 1/4 feet

3 0
3 years ago
A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou
Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let z be the

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question, x = 5 and \sigma = 2. The equation becomes

\displaystyle z = \frac{5 - \mu}{2}.

To solve for \mu, the mean of this distribution, the only thing that needs to be found is the value of z. Since

The problem stated that P(X \le 5) = 69.85\% = 0.6985. Hence, P(Z \le z) = 0.6985.

The problem is that the normal distribution tables list only the value of P(0 \le Z \le z) for z \ge 0. To estimate  z from P(Z \le z) = 0.6985, it would be necessary to find the appropriate

Since P(Z \le z) = 0.6985 and is greater than P(Z \le 0) = 0.50, z > 0. As a result, P(Z \le z) can be written as the sum of P(Z < 0) and P(0 \le Z \le z). Besides, P(Z < 0) = P(Z \le 0) = 0.50. As a result:

\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}.

Therefore:

\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}.

Lookup 0.1985 on a normal distribution table. The corresponding z-score is 0.52. (In other words, P(0 \le Z \le 0.52) = 0.1985.)

Given that

  • z = 0.52,
  • x =5, and
  • \sigma = 2,

Solve the equation \displaystyle z = \frac{x - \mu}{\sigma} for the mean, \mu:

\displaystyle 0.52 = \frac{5 - \mu}{2}.

\mu = 5 - 2 \times 0.52 = 3.96.

3 0
3 years ago
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