Answer:
25000 fragments
Explanation:
A restriction enzyme can cut a random DNA sequence once per every 4^n where n = number of bases in the recognition site of enzyme.
There are 6 bases in Xbal's recognition site (TCTAGA) so it will cut once per every 4^6 = 4096 bases (4kb).
Total genomic size = 100000kb
So expected number of fragments = Total genomic size/Size of one fragment
= 100000/4
= 25000 fragments
The answer is jellyfish B
Answer:
If you have anyone of these answer choices..Its D.All of the Above
Explanation:
A. Cells are the structures that contain all of the materials necessary for life
B. Cells are found in all organisms
C. Cells are sometimes specialized for particular functions
D. All of the above
The first is ture the second false the three is ture 4 ture 5 false 6 ture 7 false 8 ture 9 ture 10 false
In a dominant cross, the chance of the dominant phenotype showing up in one of the offspring is 3/4, since the dominant genes are being shown here.
