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AleksAgata [21]
2 years ago
9

Help me please geometry class

Mathematics
1 answer:
artcher [175]2 years ago
6 0

Answer:

m∠ADB = 59°

Step-by-step explanation:

I've provided my work which also includes how I check my answers by using the information given! Hope this helps!!! If you have any questions, I can try to help.

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How much millimeters is in one cup
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In one U.S cup, there are 236.588 milliliters. (No such thing as milli"meters" in a cup). 
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3 years ago
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Amber has determined that the experimental probability of making a free throw in basketball is 12/15. What it the probability of
nalin [4]

Answer:

3/15, 1/5, or 0.2 probability. Highly unlikely

Explanation:

12/15 is the shown probability. The leftover is 3/15, so 3/15 is the chance of missing the basket.

~Hope this helps~

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3 years ago
A drunkard executes a “random walk” in the following way: each minute he takes a step north or southm with probability 1/2 each,
valentina_108 [34]
Assume that a step to the north is in the positive direction and a step in the south is in the negative direction.

Then,

E(X_i)=50\left(\frac{1}{2}\right)-50\left(\frac{1}{2}\right)\\ \\=25-25=0

and

\sigma^2(X_i)=E(X_i^2)-E(X_i)^2 \\ \\ =50^2\left(\frac{1}{2}\right)+50^2\left(\frac{1}{2}\right)-0^2=2500\left(\frac{1}{2}\right)+2500\left(\frac{1}{2}\right)-0 \\ \\ =2500 \\ \\ \Rightarrow\sigma(X_i)=50

After 1 hour of independent steps,

E(X)=\sum_{i=1}^{60}E(X_i)=60(0)=0

and

\sigma^2(X)=\sum_{i=1}^{60}\sigma^2(X_i) \\  \\ =60(50)=300 \\  \\ \Rightarrow\sigma(X)=\sqrt{300}=17.32

Therefore, by Central Limit Theorem, the distribution of the random walk is normal with a mean of 0 cm and a standard deviation of 17.32 cm. He is expected to be somewhere around his starting point after 1 hour.
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3 years ago
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Solve for i<br><br> 3 (.5i - 6 ) = 12
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Answer:

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i=30/15

i=2

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What was the rule used for the composite transformation?
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(x, y) → (x + 1, y + 5)
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